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septic design-1994
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Last modified
8/22/2023 5:49:43 PM
Creation date
10/17/2017 12:59:35 PM
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x Address Old
House Number
3048
Street Name
North Shore
Street Type
Drive
Address
3048 North Shore Dr
Document Type
Septic
PIN
0911723320004
Supplemental fields
ProcessedPID
Updated
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� , = t-ly <br /> • MOUND DESIGN WORKSHEET � <br /> (For Flows up to 1200 gpd) <br /> A. FLOW D-7 , <br /> Estimated�._gpd (see pages D-7 or I-3,4,5) a^W*m�R���.�,y= <br /> ,..� .,.�a�,«.K�• <br /> or measured gpd. °�'°°'6 ' ° a s <br /> : � m �a �o„ <br /> . • 3 seo 70o t�� •� <br /> • aoo an as "'M <br /> B. SEPTIC TANK LIQLTID VOLUMES : ,'o ;; � '�.4 <br /> Z Z.S'b gallons (see pages C-3 or C-5) ' "" "' '�' � <br /> . �� .n .a. �. <br /> C-3 <br /> C. SOII.S (refer to site evaluation) SEVTIC TANK CAI�CIT1lS. IN {'iALLONS <br /> uuuo a...ar. <br /> 1. Depth to restricting layer = ZZ inches -�� � -^•�� <br /> �moar uaro ur�an ois►os�� <br /> 2. Depth of percolation tests = /Z- inches ,�„�„ „� ,,,, <br /> 3. Percolation rate 2 3 mpi � �«�• �••• �,•• <br /> ��� ve• �f�a <br /> 4. Land slope � % ,..a. � <br /> ,... �.e. <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> 7So gpd x 0.83 sq. ft./gpd = ZZ sq. ft. <br /> 2. Select width of rock layer(10 feet or less) = fc"� ft. <br /> 3. Length of rock layer= area+width = I <br /> ��sq. ft.+ l4 ft. _�ft. Rock Bed <br /> r.j.t•1•!•!N•1•l.l.I•r•r•I.l .� <br /> ti ti ti•ti•ti•�•ti•ti•ti•�•�•ti•L•ti•ti• <br /> 1•I.�•1•I•1•I•I 1•l•r•1•t•r•t <br /> ti.ti.ti.�.ti.�.�.�•ti•ti•ti.ti•ti.ti.ti• idth S1P <br /> �.1•I•l.t.l.l•r r•f•1•f•t•t•t <br /> � 1�.'ti�ti•���•L�ti�1�1•ti•5�.�•1�.ti�ti. <br /> .r.r.r.f.f.i.�.�.r.r.f.i.f.r.r <br /> E. ROCK VOLUME �- L�s� -�' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> ZZ sq. ft. x / ft. _(ZZcu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> ZZ �. ft. i 27= 23 �. yd. <br /> 3. Multiply cubic yazds by 1.4 to get weiYht of rock in tons; <br /> �3 cu. yd. x 1.4 ton/cu. yd. =�d tons. <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is�mpi E-16 <br /> 2. Select allowable soil loading rate from table on page E-16; �-����a��•�«��•�, <br /> �CoU gpd/ft2 ,�..� ..�.....�. � ......._ <br /> 3. Calculate adsorption width ratio by dividing rock layer �""" "'"� `�� '""" `��� <br /> �.�. � ia. f.M �.a �.w <br /> � .i� �.�s �.ts 7.» i.» <br /> loading rate of 1.20 gpd/ft2 by allowable soil loa ing rate; . .,. .... .... ,... ,.» <br /> 1.20 gpd/ft2�- ��c4 gpd/ft2= �oo „ ... ..M ..» ,N �.� <br /> ,. ... .... ..,. ,.N ..., <br /> •1 .tt� �.f� �.1� �.N f.00 <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; I <br /> �O x_�ft =�ft <br /> I <br /> I <br /> I <br />
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