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2000-P02774 - new septic system
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2000-P02774 - new septic system
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Last modified
8/22/2023 4:23:21 PM
Creation date
10/2/2017 1:49:35 PM
Metadata
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Template:
x Address Old
House Number
1720
Street Name
North Farm
Street Type
Road
Address
1720 North Farm Road
Document Type
Septic
PIN
2711823440011
Supplemental fields
ProcessedPID
Updated
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' ,�� ATGRADE DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) Estimaced Sew'�Be Flow in Gallons per Day(gpd) <br /> N o(� 'Iype I 'lype II 'Iype III Type IV <br /> A. �.�W Bodrooms ' <br /> Estimated �� gpd 2 �oo z2s ieo � i <br /> s aso soo 2is <br /> a eoo 3�s ub '� <br /> or measured — x 1.5 = -- gpd. s �so aso z�a "� <br /> 6 900 525 332 <br /> 7 1050 600 3')0 � <br /> B. SEPT'IC TANK LIQUID VOLUMES 8 12°° 6�s °°6 <br /> I-)�.So d �-i ooc>gallons Number r'°,;m"m �"°"m"m <br /> or �`„"'` �� <br /> C. SOILS (refer to site evaluation) B�� c.�.� �� <br /> 1. Depth to restricting layer = ��;,y��,�wxe.�t��inches �'"�"� �d1as' <br /> 2. Depth of percolation tests = 1.a inches 2�iess �so i.iu <br /> 3. Percolation rate `i.S mpi s o 6 i;soo i,2'�so <br /> 4. Absorption Ratio�� gpd/ft� o a 9 s fi&c-� �x�is�) <br /> 5. Linear Loading Rate: 8 6�3 2 gpd/ft <br /> 6. Land slope 7 % b^��,5� ti� <br /> � ��1 <br /> D. ROCK WIDTH �d�,,� Soil Texture r� ;w.� <br /> 1. Percolation rate in top 12 inches of soil is I�-3o mpi `"'�' '� <br /> Faster than 0.1 �se Sand �•� 1•� <br /> 2. Select allowable soil loading rate from table; o.i co s sena l.�o l.ao <br /> •�� $p�f� 6 to 15 �nd�Loam 0.79 1.52 <br /> 3. Calculate adsorption width of the rock by dividing ��� �� � • 200 <br /> 37 to 45 Silt I.oam �•� 2'a <br /> rock layer loading rate by allowable soil loading rate; �c�6o c� c,�m o.as 26� <br /> `�--ev. d/ft+��gP��2 = c,, ft. sio,61��,°�zo c�Y o.sa s.00 <br /> -seu n.�in�soli m n,o�e ot nn�o..�ery b,u..na. <br /> � E. SYSTEM SIZE Mpt <br /> Soil'I'exture O�k����v �����8 R+te <br /> - a.The Height of the System is�feet(2') Fueerehan Q1 c�,�S„rd �Neentiredepeh s <br /> b. Enter tabl�with landslope No&ndia6 s <br /> O.1 to 5 S�+d Lyees wilh no Mottln 4 <br /> andupslope dike ratio. <br /> Select dike multiplier of _ .► . L .��M�, z <br /> o.i so s F�+Q�+d 6 <br /> c. Multiply u�slope dike multiplier by =�-��= N°�""�°'^°�"°" <br /> height to find upslope dike width: U�d�� _4 <br /> e so as Sardy Loaa+ <br /> 2 ft x�Z=�e_feet 16��� �-�'�► Nod.�U� a <br /> d. Enter table with landslope and 31 to+g s���•�' �,,�„�,�,,���, 3 <br /> downslope dike ratio. 46 to 60 cur�=a► <br /> Select dike multiplier of �. 60�o z2o cl.r �t►���d��,, <br /> � Z <br /> e. Multiply downslope dike multiplier by �720 �droek eneouneartdletAeborin6 <br /> height to get downslope dike width: � <br /> � ftx SS� =�feet uS�►�S <br /> f. The System width is the sum of upslope dike width plus downslope dike width; <br /> �� ft+ 1 s� ft= � � feet � <br /> g.The rock layer length is the flow divided by LLR: c�o. +�__ �a S feet ; a�� � 3 <br /> 1. Total length is the sum of upslope dike width plus rock layer length plus <br /> upslope dike width: c� ft+ 1 i� ft +�_ft= � �S feet <br /> F.ROCK VOLUME �'x��_, <br /> , 1. Multiply rock area by rock depth to get cubic feet of rock; 'o� sq. ft.x a_o ft=2= 4SZ cu. ft. <br /> � 2. Divide cu. ft.by 27 cu.ft./cu.yd. to get rubic yards;�+:s� cu. ft. +27=J:2 cu.yd.�-A��. <br /> 3. M u l ti p l y c u b i c y a r d s b y 1.4 t o g e t w e i ght of rock in tons;�cu.yd. x'1.4 =�tons. <br />
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