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, 97/�7/2608 09:24 9528733112 PAGE 16/14
<br /> PRESSURE DISTRIBUTION SYSTEM - T�enches
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<br /> All boxad racfangfesmusf be srtMred.fhe r�stw�Tf be calcuJaOed. •�,.•.,.:;�:�:•.f,�;,,,:.r:�s:;,��� ..,Y..�:� •,...... �;;;�,;.: ��r;:;
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<br /> 1. Select number af perfcrated l�terals: 03
<br /> 2. Sefect perforation spacing= r�ft e.i; e�,n,u„aiaw,isnn,00raii��na,va.W�
<br /> pw�A a�o�r+�..ansd�doo.�aaao�
<br /> 3. Since perforations should not be placed closer that 1 foot to °�'
<br /> the edge of the rock layer(see diegram), subtract 2 feet from
<br /> the roCk la e�len h �y e ie ta ae
<br /> 63 -2 ft= 61 ft �.o e �a t� ze
<br /> rock layer length a � ;; 15 �
<br /> 5,0 6 10 14 xi
<br /> 4 Deterrnine the number of spaces between pertorations. �
<br /> Divide the length (3) by perforation spacing (2) and round down to nearest whole number.
<br /> Perf�ration spacing = 61 ft/ 3 ft= 20 spacos .
<br /> 5. Number of perForations is equai to one plus the number of pertoretion spaces(a),
<br /> *Check�igure E-4 to assure the number of perforations per latera!guarantees
<br /> � 10%discha►}7e variation.
<br /> 20 spaces+ 1 ; 21 perforationsllaterel
<br /> 6. A. Total number of perForations= perforations per lateral (5)times number ofi laterals(1).
<br /> 21 perfsl lat x 3 laterals= 63 perfarations
<br /> Fa ParioncMan Oschvpe In�m
<br /> B. Calculate the squa�e faotage per perforation.
<br /> Should be 6-10 sqftlperf. Ooes not apply to at-grades_ perfo�rafla�amerter
<br /> 1. Rock bed area=rock width (ft)x rock length (ft) ���� 1!8 3/ib 7/32 1!4
<br /> 10 ft x 63 ft= 630 ft� �,pa 0.18 0.42 0.56 0.7d
<br /> 2_ Square foot per pertoration=Rock Bed Area/number of perfs(6)
<br /> 630.0 ft2 / 63 perfs = 10.a ft2/perF 2A�'' 0.2b 0.59 0.60 1.04
<br /> 5.0 0.+11 0.94 136 1.65
<br /> 7. Detemnine required flow rete by multiplying the total number b uoe i,o root ror gny�o.r�rv�v�.
<br /> of perforations(6A) by flow per erto�ations(see figure E-6)
<br /> 63 perFs x 0.56 gpm/perfs= 35.3 gpm .
<br /> 8. If laterals are connected to header pipe as showm �,��_^�;?h�%�p„M�,
<br /> in Figure E-1, to select minimum r�equired lateral �r�-�"J ��r-�.�'�%
<br /> diameter,enter figure E-4 with perforation spacing(2)and �r.av ��..�_-� ��.�
<br /> :
<br /> number of perforations per lateral(5). ���� ^ u n�;�,���,
<br /> wpiw�!•1:Ms+�bla�.eeawd a�4nd d pyN�n�
<br /> SeleCt minimum diameter for perforated laterals� Qinclies���������""�"�..""'."._._,...._.____..__.. __..—
<br /> 9. If perforated lateral system is attached to manifold pipe a��s:M�rwaw�.a .,�=•d^�
<br /> nearthe center, like Figure E-2, perforated laterdl length (3) �' a�'���"�'" ��~�- f��'
<br /> .-r,�Taraaoer ��x^--"'
<br /> and number of perfcrations per lateral(5)will be approximately ��---' ^����- .���T
<br /> one half of that in step 8. Using these values, select �=-�^ ..�� `=`� �-�
<br /> .='�r�'"t^" --^" �'"'�c`"a"""c'
<br /> minimum diameter for perforated lateral= 02 inches. �--�.��-
<br /> rr-.f-- w•aM�vna
<br /> 1 here y ify that I hav ompleted this work in axordance with all applicable ordinances, rules and l�ws,
<br /> (signature) �,SG�2 (licens�#) � �/ (date)
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