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1993-005616 - new septic system
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350 North Arm Lane - 06-117-23-24-0014
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1993-005616 - new septic system
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Last modified
8/22/2023 5:25:51 PM
Creation date
9/27/2017 12:48:16 PM
Metadata
Fields
Template:
x Address Old
House Number
350
Street Name
North Arm
Street Type
Lane
Address
350 North Arm La
Document Type
Septic
PIN
0611723240014
Supplemental fields
ProcessedPID
Updated
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� <br /> . , G. . DOWNSLOPE DIKE WtUTf� � <br /> ' 1. �f landslope is 2.9 percent or less,basal width includes both the ! <br /> upslope and downslope dike widths, , <br /> � 2. Calculate minimum mound size based on geometery: ' <br /> a. Determine depth of clean sand fill at upslope edge of rock <br /> layer: Separation l.3 feet , . � <br /> b. MulHply rock layer width by landslope to det•ermine drop ! <br /> in elevation;Slope Di�'ererrce 1MiOi"' '���: � � <br /> 1Q_x�_96+ 100= -"�- feet ( <br /> _. t . <br /> c. Add depth of clean sand depth of clean sar►d for �� ' � , .s* � j <br /> ... t : <br /> .. <br /> .�_ ' <br /> �..� �...��.�..." <br /> separation at upslope edge(2a)to depth of rock layer to �.� ._..... <br /> rocic depth and the depth of cover to find the total mound ,,,,;`� <br /> height at upslope edge of rock layer; . � . �`�.� <br /> ��ft + 1 ft + l ft=�,�feet ! ' <br /> d. Enter table on page bottom with landslope and upslope � <br /> dike raHo. Select dike mulHplier of �.'7 f ; <br /> e. Multiply dike multiplier by upslope mound height � � ; <br /> fio get upslope dike width:�_x 3.7 =��feet ; <br /> � ; <br /> f. Add the deptli of slope difference(2b) to the upslope ! <br /> height to get the downslope height_�+�� 3• S"feet � ; ` <br /> � ,' <br /> . g. Enfier table on page E-18 witli landslope and downslope , <br /> dike ratio. Select dike multiplier of �.`�' � ' <br /> h. Multiply dike multiplier by downslope mound height � " <br /> I <br /> to get downslope dike width: 3. S x �. '"__�,j'_feet ' . <br /> �"� i. Mininmum mound width is the sum of upslope dike ' <br /> width plus rock layer width plus downslope dike width• '••' 'f�•• • •'r•:•' r• :j � <br /> . 2 <br /> •��tiyt��i�� Stiy��• ti M .�.�ti14 •jti <br /> .;. ti�.,S'•: .�'. . <br /> -__ _ --- _ _� <br /> � r::::?r:?s:!;srt�tr:;rr°fr; r.•r.:r.�ti��:4:ir;tf+i si ti <br /> __ft*__------- Ft + :.:.:. :• <br /> , __ f f= feet R« e�a w�dii�10 :.�:;�� �-�...f%''��..� <br /> ..� ,;.;.. , , . , .iwu <br /> j. Subtract the Minimum width G.i�rom the Absorpdon ' ''''�� �•:••; •:;.;~` ; {,;;'' y{yj;`�`''�;� <br /> :�;:�:{ �:;;;;• <br /> width F.4 to find the Additional Downslope required for R �"� � r <br /> Absorption �;:_ :::...::::::::::r �• :�:•:r:r:�=r:;.::.•.:r:a:�::::.0 ti�:; <br /> . : <br /> •:. <br /> '{a�,r• ti{.,1•,;•.ti•.ti•.{�:���L�L{'�'��'ti <br /> .•:. ��� <br /> t�' Upf�DplUR! Iddl_L'�c .._ti• . 5.::•:{•t.':llpt <br /> ----�T-----��t=-__---- feet .u: .s::::.:r ti�s.)..},...)°��);..,u"' <br /> �:'��•SyS•••ti�N�ytySy��Sti•yS•�lyfyl 1 S'�1ryd��1 �hfi'�.y� <br /> .•r.�r s:.�i�:.•:.: •r.� Si tir.ti::+.:••r tis tir sr�r sr:r st..r i <br /> k. Add the Additional Downslope required for Absorption•�r���;:r y�tir�::ws,,��••.����{:.�:�����,;, <br /> •:..::. r..t t. .ti.,�.,r. ., <br /> to the downslope dike width and recalulate the Total �'�"�'''"''`''�`''"''��' )�) � ) ) w <br /> . c•.{•.e�.t••:•.•. {; . <br /> 'ti:;�rr�:.�rftit�;.tir.tr�:. ;ttj'�r'Srf'�t'tir'+a'�r r'N'L'+t'V'4'tir <br /> ti� i �S��i� ti�ti�� tiitil4�ti�tiSti�yhyY�4 <br /> Mound Width which is is the sum of upslope dike '•��_���``��s''• �''a.`'.{"�•''•"`�)`'}�'•'ft'c's:'.` <br /> : M:�'�. A tiYYS ti�ti1yS�•S 1ti 1 <br /> ��{�t;''rti.�;. ;tie.•.r;{;�t;�t�t{.•;.�lr:;•�t•s:rti$sf I <br /> width plus rock layer width plus downslope dike width `'~' ; <br /> ,�_ft+_�ft+��ft =��feet �-T°��"'�' ��'' --� <br /> 1. Total mound length is the sum of upslope dike width � <br /> plus rock layer length plus upslope dike width; ; <br /> �ft+��ft+ IZ ft= _ �r2feet <br /> IS G � /S � � I <br /> x� aM s�ima� �� r.� �� �:� �� �> >:� �:� i <br /> s <br /> 0 � S.0 LO S.0 6.0 7A 3A {.0 S.0 6.0 7A LO I <br /> 1 3Ai {.17 S.2i �.�/ 7.53 211 1.76 S.ib iSl 7A1 ' <br /> 2 a.l! SS6 6.l2___-.---Ll� 2t3 3. �.5� 536 �.1� 6.lD ; : <br /> • T--7�'-� 5.M --7.32 !.!6-_ -"I. � S.O6 S.7! 6,15 <br /> � � 3A1 �.76 6.75 7.l9 9.T2 2E! 3.6 {,17 !.!1 5.�6 6.Q6 <br /> S !S3 5.00 6.67 l.57 10.77 261 333 1.00 1.62 5.19 57l i <br /> 6 3.66 5.�6 7.1� 9.31 12.07 t51 3.7! �.lS �.�1 �.f� SAt ; • <br /> 7 �JO S.li 7.M 103{ 13.77 iM 3.12 3.70 l?J 4.7U 5.1� � <br /> / 9.�5 S.M {.31 113� 15.9t 2�2. 3.Q1 3.57 1.� {,N �J/ � �' <br /> 9 l.It 6.�5 9.09 1�.01 1l.92 2.36 t91 3.15 3.90 1.30 �.AS"' <br /> 10 �29 6.O lOA 15A0 �333 2.31 2.l6 333 3.75 1.12 {.N <br /> il �.Y ' 7.1� It.11 17bS �OA3 tId 2.7! 3.73 �.61 !.% ��6 i <br /> I2 �.bi 7.69 1250 21A3 IJ.75 t21 2.T0 3.12 3A9 �.l0 IA! <br /> 1 <br />
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