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. > <br /> F-17 <br /> r�rntp SEr.F_r_r_rnN PROCEDURE � <br /> .ENp PERFOFATI�1 OF A PERFORATED LATERAL <br /> A. Determine pump capacity: �v•• <br /> Gravity Distribution *«� r+,�, � <br /> i. Minimum suggested is 600 gaIlons per hour(10 gpm)to stay ahead of •: :�;�,,,�,,,,w F,e,k�,,,,,- <br /> water use rate. ,:' `�'�� ��'•��'�u�� <br /> � N��na.ow o�l <br /> 2_ Maximum suggested for delivery to a drop box of a home system is 2,7Q0 __ . ro��,,,.a,"»�"��_°^'°"r <br /> gallons per hour(45 gpm)to prevent buiid-up of pressure in drop box. .;�,•�„„ "-u ��,� �z•�o Eaa. <br /> a Fhld o1 Roct LofM <br /> . ... . .... �Prlorarlar lacelW ol <br /> Yressure Distibution �"'"S"°�" �°"°'"`�`•�•"� <br /> 3.a. Select number of perforated laterals � . <br /> b. Select perforation spacing=�_feet ���;��«'"° <br /> c. Subtract 2 ft.from the rock layer length. <br /> �S -2 ft.= r _feet � <br /> x��ye�u <br /> d. Deterrrune the number of spaces between perforations. <br /> Length perf.spacing=$�ft.+�,ft.=L2 spaces Requirea PerEordeon D�cn e <br /> e. �spaces+1 =�_perforations/laterai �+�u°i`s p�`II"I'°ce(gp"� <br /> f. Multiply perforations per lateral b�,' number of laterals to .�`dse �Z ID��", 4°'�'�'` <br /> get total number of perforations. W�e�s x � ��_�perforations. �fee�> <br /> g� � "`�°'2'�`-�gP�� 1.Oa 0.56 0.74 <br /> SELECTED PUMP CAPACTTY��gpm 2.Q�j �.SO 1.Q4 <br /> B.Determine head requirements: a.Use for single family homes <br /> 1. Elevation difference between pump and point of discharge. b.Use for all other appl�cations <br /> ___�_�_feet <br /> 2. If pumping to a pressure distribution system,five feet for pressure <br /> required at manifold if gravity system,zero. <br /> S feet <br /> 3. Fricbon loss ' � <br /> a. Enter friction loss table with gpm and pipe diameter. � P'Pe LeRS�' J <br /> Read friction loss in feet per 100 feet from table. ` Poinc of D�s�h�ge <br /> F.L.= a.(�� ft./100 ft of pipe �D3 <br /> b. Deternune total pipe length from pump to discharge Elevadon Difference� <br /> point. Add 25 percent to pipe length for fitting p�,p qZ <br /> loss,or use a fitting loss chart. Equivalent pipe <br /> length-1.25 times pipe length= F-18b <br /> a1�' x1.25=��feet <br /> 1.5 inch 2.0 inch 3.0 inch <br /> c. Calculate total friction loss by multiplying �m friaim lm pa IOOR of pipc <br /> friction loss in ft/100 ft by equivalent pipe length. 10 0.69 0.20 <br /> Total friction loss= �'�o�i x a(� 41 +100=�_feet 12 0.96 0.28 <br /> 4. Total head required is the sum of elevation difference, 14 1.28 038 <br /> special head requirements,and total friction loss. 16 1.63 O.a8 <br /> 18 2.03 0.60 <br /> 20 2.47 0.73 0.11 <br /> �_+ � + � 25 3.73 1.11 0.16 <br /> (1) (2) (3c? 30 5.23 1.55 0.23 <br /> 35 7.90 2.06 0.30 <br /> 40 11.07 2.64 039 <br /> TOTAL HEAD ��feet 45 1a.73 3.28 0.48 <br /> 50 3.99 0.58 <br /> 55 4.76 U.70 <br /> C. Pump selection � ��� 0�8Z <br /> 1. A pump must be selected to deliver at least <br /> �►� gpm (Step A) with at least �feet of total head (Step B). <br />