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- � ` ' "� MVU1vL Vn�1�1�t n►Vnn�riCnl <br /> ' . � (For Flows up to 1200 gpd) <br /> A. '�OW � E�timated Se�va=e Elows ia GaUoos per day <br /> ( <br /> Estimated 7 S� gpd ra� ;�cy�i ,yau r,�m �, <br /> or measured — x 1.5= — gpd• <br /> Z 3ao � iso �, <br /> B. SEPTIC TANK LIQUID VOLUMES 4 � �s 2� � <br /> 1—�d,.f0 �l-100� �OTLS � 6 90o Sts 33z Tya� <br /> : 7 � I050 600 370 p« <br /> ; 8 � t200 673 I 408 m <br /> C. SOILS (refer to site evaluation) ' `��' <br /> 1. Depth to restricting layer= � �� a�= inches — feet � �� ��r <br /> w�r�r w.�ua.�. a�v.�r-� �� <br /> 2 Depth of percolation tests= ��. inches °°� �' �'�' <br /> 3. Texture L.o�.,n Percolation rate �. y mpi =3�.�' � �� � <br /> s�w ti i soo nso �aoo <br /> 4. Land slope (. % �.A�KY � � •� <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer. A x 0.83 = <br /> �SO gpd x 0.83 sq. ft./gpd =�sq. ft. <br /> 2 Select width of rock layer(max 10' if<120 mpi max 5') _ /o ft. <br /> 3. Length of rock layer=area+width� �s.w •w ,... ...�.... <br /> «...�� .X,. '`�+a: , <br /> �a z sq. ft. + /0 ft. _�_ft. :r;�°�r��;,��3� <br /> o. p.. <br /> Width�ft � . a o . , '� <br /> <120mpi <10' Length�_ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�a .sq. ft. x 1•0,� <br /> ft. =S�.cu. ft. <br /> 2. Divide cu. ft.by 27 cu.ft./cu.yd. to get cubic yards; <br /> �,�,cu. ft. =27=�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;�cu. yd. x 1.4 <br /> ton/cu.yd. _�tons. <br /> F. ABSORPTTON WIDTH ��s�a�k <br /> 1. Percolation rate in top 12 inches of soil is �.0 mpi �� �T� �� ��� <br /> Texture L�-�`�t Lo x}-,r� cr+Pn �ra« t,ra��am <br /> � 5.w m.e o.i c.o�s.ea ��o i.00 <br /> o.i oos s�ea i�o i.00 <br /> 2. Select allowable soil loadin rate from table; o.��s F�s� o.�o :.00 <br /> 8 6 w IS Saodr L.oam 0.79 1.52 <br /> ,4� OTfd/ft2 ' i6pw � o.eo z.00 <br /> OC 31 ro 43 Silt L.a�m 030 2.a0 <br /> , �6 ro 60 (7ay L,o�m Q45 267 <br /> 60 ro I20 qay 0.?A 5.0� <br /> 3. Calculate adsorption width ratio by dividing rock layer �"°"'�iAie120 � oso s.00 <br /> loading nte of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ftz+ .�t� gpd/ft2= a-t�7 <br /> 4. � Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> � �.,�x iv ft = a�. ft <br />