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1993-005536 - new septic system
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1993-005536 - new septic system
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Last modified
8/22/2023 5:26:11 PM
Creation date
8/28/2017 11:53:52 AM
Metadata
Fields
Template:
x Address Old
House Number
540
Street Name
North Arm
Street Type
Drive
Address
540 North Arm Dr
Document Type
Septic
PIN
0611723310006
Supplemental fields
ProcessedPID
Updated
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, �p2.oPo s� E-i� <br /> . ;� • �� MOUND DE3IGN WORKSHEET <br /> . . � (For Flows up to 1200 gpd) <br /> A. FLOW . � � D-7 <br /> Estimated �o o gpd (see pages D-7 or I-3,4,5) p'"r"�'D�'�■«���' <br /> N�awtn trw.aF utsro�rcc <br /> or measured — gpd. , , �• � n m a <br /> . � n, �.� .o. <br /> • s .eo aoo eu � <br /> B. SEPTIC TANK LTQUID VOLUMES ; ,� „; � ^g.'� <br /> � �� .» � <br /> � - i o v a. gallons (see pages C-3 or C-5) � • �� •n � �» <br /> C-3 <br /> C. SOILS(refer Eo site evaluation) .�.nc AMC CAIApTIl� pl OAILON� <br /> 1. Depth to restricting layer= z��� -�u 3�'� inches �,,: �: .`�•�• <br /> 2. Depth of pereolation tests = � �. 1AC11eS i au� n� »u <br /> 3. Percolation rate � . 4� mpi �«�� �N: ,N. <br /> 4. Land slope � % �°"• ,"' "�• <br /> �aa• „a �w� <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of roi�k <br /> layer:A x 0.83 = <br /> le o o gpd x 0.83 sq. ft./gpd =��sq. ft. -r t o�� 547 <br /> � 2. Select width of rock layer(10 feet or less) = I a ft. <br /> 3. Length of rock layer= area+width= � <br /> y� sq. ft.+ � c� ft. _��ft. Rock Bed <br /> � � /'.f.�l.�r.�f•r.�.f. r. <br /> . . '►•ti.ti ti•ti•�•'1�•ti�ti•�•ti•ti•ti•'.1• <br /> .t•f•t•t.fN.Ht•r.f•ht•�'t•1 �}I ���. <br /> ti�ti�ti�ti•1 1�ti�ti�ti�ti�l�ti�ti�ti�ti� <br /> � ' t•J•r•f•t•1'•t•t•I•f•t•r•t•t•t <br /> � � ti•1•\.ti•ti ti•�•ti•�•ti•1•ti•ti•\•S• <br /> . .l.r.t.f.f./•t.p.f.r.f.f.r.r.f <br /> E. ROCK VOLUME �— �gw � <br /> 1. Multiply rock area by rock depth to get cubic feet of rckk; <br /> ti� sq. ft.x �.�s ft. = 5�y cu. ft. � <br /> 2. Divide cu.ft.by 27 cu. ft./cu. yd.to get cubic yards; ' <br /> 5�y cu. ft +27= a.L cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �]_cu. yd.x 1.4 ton/cu.yd. _�tons. <br /> F. ADSORI'TTON WIDTH <br /> 1. Percolation rate in top 12 inches of soil is ��.�mpi E-16 � <br /> 2. Select allowable soil loading rate from table on page E-16; •�•�•�••••�•a••••••••�•»• <br /> • 1�r gpd/ft2 ..�... ,r.,�..,..�. . <br /> �w IYr A MM1� <br /> 3. Calculate adsorption width ratio by dividing rock layer ""` """ `'"" """ '""`"'"' <br /> ..,. . .... ... ..» ,... <br /> . .,. ..,. ,.,. .., ,.� <br /> loading rate o 1.20 gpd t2 by allowable soil loading rate; ,. .� ..« ..� ,... .:: <br /> f� .�� �.N �.N t.M t.N <br /> 1.20 gpd/ft2+ .� <' gpd/ft2= I .Sz .• ." •." "„ ,�' •" <br /> �t .�N �.I� �,N �.N 4N <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> „� �o x �• � ft�i�'ft <br />
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