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G. DOWNSLOPE DIICE WIDTH �
<br /> 1. If landslope is 3�0 or more,subtract rock layer width from
<br /> � adsorption width to obtain minimum downslope dike toe
<br /> �r..� ft-,/o ft=�_feet
<br /> 2. Calculate Minimum mound size based on geometery:
<br /> a. Determine depth of clean sand fill at upslope edge of rock
<br /> layer: Separation �.� feet
<br /> b. Multiply rock layer width by landslope �� reo� co�.�. .
<br /> to deternune drop in elevation; � � rooc Ro aa
<br /> Siope Di�E1'eTICE S�peretloa � fe�t _
<br /> _�feet s�ov� D����rence�� et
<br /> /D x �,� %i 100 = , uos�oo�w�atn
<br /> c. Add depth of clean sand for sepazation (2a) --�3-feet Roce eeo wtotn
<br /> at upslope edge,depth of rock layer(1 foot) to depth of �_teet Downslope W1GtN
<br /> cover(1 foot) to find the mound height at the upslope edge �-ieet
<br /> of rock layer;
<br /> �.J ft+ lft+ lft= y.� feet
<br /> d. Enter table with landslope and upslope dike ratio.
<br /> Select dike multiplier of 3.3'3
<br /> e. Multiply dike multiplier by upslope mound height
<br /> � to find upslope dike width: y.o x 3•3-� _�'�feet ' �
<br /> f. Add depth of clean sand for slope difference(2b) at
<br /> downslope edge,to the mound height at the upslope edge
<br /> of rock layer(2c) to find the downslope height;
<br /> y.� ft+ .J/ ft= 4.�feet
<br /> � g. Enter table with landslope and downslope dike ratio.
<br /> Select dike multiplier of s
<br /> h. Multiply dike multiplier by downslope mound height
<br /> to get downslope dike width: �t.S x S�_��_feet
<br /> i. Compare the values of step G.1 and Step G.2h Select the
<br /> greater of the two values as the downslope dike width; L3
<br /> :.>..
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<br /> u slo dike width G.2e lus rock la er
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<br /> s.aps
<br /> 0 3A LO 5.0 6.0 7.0 3.0 6.0 5.0 60 7.0 8A
<br /> 1 3A9 U7 526 638 753 291 3.8'a d.76 5.66 651 7.�1
<br /> 2 3.79 {.3S �56 6S2 8.1� 2.83 3.70 65� 536 6l• 6.90
<br /> 3 330 l31 5.88 7.32 8.bb 2Ta 357 �35 5.� 5.79 6.15
<br /> � f 3A1 l76 625 7.89 9.72 268 3. l.17 �.81 5.16 6.06
<br /> _5 353 � _667 SS7 ]O77 261 l.00 {.62 3.19 5�1
<br /> 6 3�-S�li 7.11 938 12W 251 313 3.85 {.11 443 S.�]
<br /> 7 3�0 556 7.69 103� 13T3 268 3.12 3.7G �2i 1.70 5.13
<br /> 8 3.95 SB8 831 115f 15.91 242 3.Q! 3,57 l.QS 1.{9 �88
<br /> 9 l.11 62S 9.OD 13A1 18.92 236 29{ 3.15 3.90 1.30 4.65
<br /> ]0 �29 667 l0A 15.00 ?333 231 286 337 3.75 f.12 I.N
<br /> II 4.�6 7.74 11.11 17.65 30.�3 216 278 3.73 3.61 3.95 �?6
<br /> 12 lb9 7.69 1250 21.13 d375 221 2TJ 3.12 3.t9 3.80 �.OS
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