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septic info including 2006 design
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0300 Sixth Ave N PID: 25-118-23-41-0001 - OLD PID - Now: Mooney Lake Preserve
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septic info including 2006 design
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Last modified
8/22/2023 4:15:00 PM
Creation date
7/31/2017 8:30:09 AM
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x Address Old
Address
0300 Sixth Ave N
Document Type
Land Use
PIN
2511823410001
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� . _ �Gv �;�� r�'tcQ �!� ,'G)2afv� /7l.-�,.: <br /> MOUND DESIGN WORK SHEET (For Flo�vs u to 1200 d) �. <br /> . Average Design FLOW <br /> �� A-t: EsNmatecf Sewoge Fbws in GaUons per Day <br /> � � �� t�:�.� : <br /> Estimat�d G cx� gpd (see figure A-1) �drooms c�ass i ctass�t ciau ui c�osr <br /> or mea�ur�d x 1.5 (safety fnctor) = gpd 2 3� 225 �so oati � <br /> �-� 300 216 or rr;,: <br /> . SEPTIC TANK Capacity �`� � 375 25c �a��s <br /> 5 750 450 2"v=: �n ln.. <br /> 6 90t� 525 332 Cloas t. <br /> _L ' �����all�o�flgure C-T) 7 1050 b00 370 ��.�r��� <br /> �� - • 8 1200 675 408 columrs. � <br /> . SOILS {refer to site evaluation) ��. � �,��k4� ,��«b �i��y <br /> N <br /> �� Numbcrof Mini�uwn d Jc �iJ;;�..:i� <br /> 1. Depth to restrictirig layer= �= O feet --�(� �� �"' �'4"' '�'��}���� a•��i,a�.:...�,s <br /> s�a►W►� c:�:�nr s���,�sa� m�u��.a:: <br /> 2. Depth aE ercolation tests = 1 �[� feet j Z,, : � <br /> 3. Texture �t " L.�r�i4-�� �✓�.Q-_ �!G _ �;�, ,h,. ; "-� <br /> r`'' ma aoo �u,o ;��;� <br /> P�rcolation rate3`-f•/ mpi ���'�- � s��y ;�� a� :,,.,, <br /> 4. Soil loading rate C� • �, d/sqft(see figure D-33} "''" <br /> 5. Percent la�zd slope�_% <br /> . ROCI: LAYER DIMENSIONS <br /> 1. Multiply average design flow (A) by 0_83 to obtain required rock Ia er area. <br /> t�cx� gpd x 0.83 sqft/�pd = ��k-� sqft •� (a�ic � SaG� C..� <br /> 2. Determine rack layer width= 0.83 sqft/gpd x linear Loading Rate ( LR) <br /> 0.83 sqft/gpd x !'Z gnd/sqf� /G ft <br /> 3. Length of rock layer= area +width = , _, Mound LLR - <br /> 5�� sqft(D1)+ f� ft(D2) = 5 � ft <br /> � . < 120 MPI <12 <br /> . ROCK VOLUME � <br /> . � > 120MP1 < b <br /> 1. Multiply rock area (D1) by rock depth of 1 ft to get cubic feet of rock <br /> -5�� sqft x 1 ft=�'S�� zuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> �a�� cuft +27 cuyd/cuft=�_cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons <br /> �„(_cuyd x 1.4 ton Jcuyd = 5 R tons � �p � <br /> D-33: Ab�urptfou W[dth Sixtn6 TuWe <br /> F. SEWAGE ABSORPTION WIL?TH , �,�o�,,;�R�� �;„'k�,� <br /> in Mimiw per 5.,i1 Tc�cturs Galhau Al.�.npu�,,, <br /> laell per d'ry pa Ilau.. <br /> Y l'IIN <br /> f'C{lCf 1�1U1 3 (.11i11aC�YII, �.�Il (.W <br /> Absorption width equals absorption ratio (See Figure D-33? Mw,��� <br /> �.,�:.��y s.�., <br /> times rock Iayer width (D2) --- - ''�^�S�-� -- � � <br /> ---ololi_... ��m+J,yLacu�..._-- RT'.-- i+u <br /> �Q_��,_ l.wlm U.a� - ?.�a� <br /> � <br /> � x �G ft=_�Z ft .�+�.\ ' s�ia��--� --- u�„----� �„- <br /> 'r ln w oa ) �«�y Cny t.�.� '� u.�s 7.n� i <br /> �,J i�uY Cley Luwn y ..r -..__�-- <br /> �7 t tay�.�tYtq_ . <br /> .'�-9-- '�j�G --�O G /Yl.r � _....6;w i�i_.. �,�3.c,.Y - a�: s.+�, <br /> �:u Ci.y <br /> ..Slnwrrtbm 12U' . .� <br /> �� ��,�,.�S� �. S< ,.C.Q. - .--- - <br /> � i •s..�.w.r.cxe.r w�.�...i.Mw e�w«�..i�n.,...,.. <br /> C�r Q„�/'�=� <br />
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