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� � ��� .:� <br /> � '�' OSTP Pressure Distribution UNIVERSITY <br /> Minnesota Poilution Design Worksheet OF MINNESOTA <br /> Control Agency <br /> 1. Select Number of Perforated Laterats in system/zone: �� Minimum <br /> L� <br /> (�feet is minimum nnd 3 feet is moximum spacing) '''"�°`��S�3-e�"� ���r�°d` <br /> 2. Select Perforntion Spacing: 3.0 ft I - '��-- - <br /> 9'of rock <br /> 3. Select Perforation Diameter Size 7/32 inch Perfaation s¢ing:'/.'w�i.• <br /> PertnraHon adn :2'to3' <br /> 4. Length of L.etern(s =Media Bed Length-2 Feet. Perforation can not be doser then 7 foot from edge. v 11.05.31 <br /> 57 - 2ft = 55 ft <br /> 5• Determine the Number of Perforation Spvices. Divide the Length of L.oterals (Line 4) by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Numbet of Perforation Spoces = 55 ft � ��ft = 18 Spaces <br /> 6. Number of Perforctions per Lateral is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Lateral = 18 Spaces + � = 19 Perts. Per Lateral <br /> Check toble below to verify the number of perforations per latera(guarontees less than o 10%discharge vnriation. The vo(ue 1s <br /> double rf the o center monifold is used. <br /> �-::. - - - - - - <br /> ,,� <br /> _. <br /> F_�F�-��-���, !�.1(:a����f_ _: . " -- - - <br /> � ��. . <br /> t�for�:on sv�+e t�? • �uiameter�ry�cE�1 ��s �IPE���?' - <br /> a �� rv� 2 a #�i a tw ta 2 s <br /> '�"���T��''-_..',r�_..,.,�� ' -�.#.�'�F ei.n���`'r �:.,��,.:..�:� .. .�a.�.�. �..; .._.5; .�i,M1i. _ ' . .�.�.r. <br /> � .�. <br /> . . .. .. ... . <br /> � e ii t•� ss s� <br /> sx� � 3� io � a•i <br /> , _ � � .- , ,. ��s��,y;�� � ;:� � y,� �� � - - <br /> -.��'��a'3��`1;t���� t..'-..5- .:-:'F�F'�-�.F'�.� , . '- .µ�.�a�x..� '....:._ <br /> . .-�.., x,' 3 . ' f' ' . �. . <br /> 3/l6lnd�PerioradaEa t , ,� ._ 2/�Inch Pe�3o�aiio� <br /> p����� �+,��� Pipr Diarna4r(Inel�') <br /> Prrfinerir:on 3v�+s iFe.t3 � � � 2 y ,�.e# 7 1K m 2 s <br /> —tr� �g�;��=�� a.�._, �mF�}�,�?�s .rt�._.. r .ti�_„ �'i�: 'v �'c ' r� 5. <br /> �...... . .. .._ . . _.. <br /> _.. . .:..� ' M <br /> ���'(�xF�-��p.�.wi��l�^�Ik • 1 ' a . � ._ : a. .... . . . . . . <br /> 2H �2 t7 24 �f3 i6 7� 2Q 3d 41 � 136 <br /> ��. - �..w -.. _ .. _ �. .���et - _ : <br /> . ., . . ._._.. <br /> '. <br /> - . . _ �. . ..�__ ...- ,-: ,m. .�:- _ " <br /> � . . ..:... .� :'..� �. . . . <br /> - - — 1 <br /> 7• Total Number of Perforations equals the Number of Perforations per Laternl (Line b)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 19 Perf. Per Lateral X �Number of Perf. Laterals = 57 Total Number of Perf. <br /> ,, . <br /> ; . �.:,,;�._.. <br /> 8. Calculate the Square Feet per Perforation. Recommended value is 4-10 ft2 per perforation. ''� ' <br /> r.rtar.ao�vum�.dr <br /> Does not oppt y to At-Grades "id�R� +,, •f„ ��� �� <br /> Bed Area = Bed Width(ft)X Bed Length (ft) � - ' <br /> /3 OaT2 �O:S1 O:fi 0.l� . <br /> 10 ft X 57 ft = 570 ft� - � o.� :p:� o:n t.xa <br /> Square Foot per Perforation =Bed Areo divided by the 7ota!Number of Perforations (Line 7). 4•0� o�'� �o�+� S:4' y,�� <br /> � �:�wveutnyca.ntN.ei,eSneea„;u�ek <br /> 570 ft� - 57 perforations = 10.0 ft2/perforations '�°°` ��� <br /> owe[tfngwl[h�Ste�ineh v�raeioes <br /> 3�teec herea�b[trhma�santla�tSTS�rAth'atte: <br /> 9. Select Minimum Average Head: 1.0 ft "�''°°'�";""'°`�°"'�'° <br /> S:f�et ��hmr�a�an�i675.Mtlr.fYO�MaA- <br /> NfelKb�'s. <br /> 10. Select Perforation Discharge (GPM) based on Table III: 0.56 GPM per Pertoration <br /> 11. Deterrnine required Flow Rate by multiplying the Total Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br /> 57 PerForations X 0.56 GPM per Perforation = 33 GPM <br />