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' • MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> , / Eatimatcd Sewage Flowa in Galloas per day <br /> A. Fr..ow , d <br /> Estimated �S� gpd ►v�« i�� �n r,�m � <br /> or measured - x 1.5 = - gpd. <br /> z �oo zzs ►so �, <br /> B. SEPTTC TANK LIQUID VOLUMES 4 � � 2� �� , <br /> _ / �1t s �so aso z4a ;� <br /> ���e�+J��' 1-I 0 O O d110I1S 6 900 525 332 Type L . <br /> g � �oso eoo 3�o Q a � <br /> ; 8 � 1200 675 I 408 m <br /> C. SOILS (refer to site evaluation) '"3 "`',��s y � : '� <br /> J S£ 1`6 ' Trh � � <br /> 1. Depth to restricting layer= �:��3�i,�t=inches feet ��r <br /> � ��� w�� <br /> 2. Depth of percolation tests= �a" inches "h�°�°` <br /> :�.w. �w iixs �soo <br /> 3. Texture �o�a w� Percolation rate y.� mpi s,K� �� �� � <br /> S a A IS00 2330 7000 <br /> 4. Land slope � % '•""y '°°° 300° "'°'° <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83= <br /> �So gpd x 0.83 sq. ft./gpd = l,aa, sq. ft.-��o`���_ ��'�� <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ /o ft. <br /> 3. Length of rock layer= area+width= : �-p:.x. � yh .y�-�. ` <br /> 0�4Yw o�� O�� 'P�;. ''��"., <br /> a..,r�.4�r����a r: <br /> ��d 4 S ft. -� �_ft. _�ft. �..�.��4f.?.... a�«�d', 1?�. <br /> q• ,(�4yQ1A'�wQl'tirW.yrr.i.�.wq{�' . �. .� . . . . ...� . <br /> : p'p'p G. f�y �'' � ... .. ,: ..: �` � .:: .:. �� ;. <br /> ^. <br /> Wldth /O ft °... . . : : <br /> <120mpi <10' Length�_ft <br /> E. ROQC VOLLTME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; ��4 sq. ft. x �.d.f <br /> ft. _�cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu. ft. -:-27= a� cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;�cu. yd. x 1.4 <br /> ton/cu. yd. _�tons. <br /> F. ABSORPTION WIDTH ne��e�wiam sm��nbi� <br /> 1. Percolation rate in top 12 inches of soil is y•� mpi e�a�wa� c�.u� woa�� <br /> Texttu'e � �1`� M+� i�e sai r�� �«a.y� ,�em�o� <br /> � troa�l cM� �q�e ro« �ay�r vram <br /> Fauer t6an 0.1 Cwete Saod 1.20 I.00 <br /> 0.1 to S Saod 1-0 1.00 <br /> 2. Select allowable soil loadin rate from table; o.��s F�a s� o.�o z.00 <br /> S 6 w IS Smdy L.oam 0.79 1.52 <br /> 16 ro 30 L.00m 0.60 2.00 <br /> •y s SPd � s,�.s s;u� oso Z.ao <br /> a6�0 6o cr,r� o.as z.a� <br /> 6ow�xo a�r o.�a s.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer S'°""'"'°120 �Y o.20 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2+ .y.� gpd/ft2= .a.�� <br /> 4. � Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �.�� X /o �- a�. {{ <br />