Laserfiche WebLink
�4s.es�u-r� , <br /> s�,„.,�c Job#� <br /> �-.«�.:�.� <br /> Pao�*e�eie ,,, <br /> Un�v�r�it�►of I�in�esota Mound Design�Iforksheet <br /> Greater than 1°h Slopes <br /> A FLOW <br /> Estimated 600 9Pd(see figure A-iJ <br /> or m�ured x 1.5(saf�y fador)= 0 9Pd <br /> B. SEPTIC TANK UQUID VOLUMES <br /> Septic tank capacaty 3000 gallons(see figwe G?) <br /> Nurt�of tanksl� 0 <br /> Eifluent�It� (yeslno) yas <br /> C-1 Septic Tank Capacity in�allons <br /> Number af Minimum Capacity with Capacity wiUs <br /> Bedrooms Capaaty Garb.Disp. Disp.and lift <br /> 2 or less 75Q 1 i25 `9500 . <br /> 3 or 4 1�100 1500 2Q0�: ` <br /> 5 or6 1500 2250 3000 i <br /> 7,8 or 9 2U00 3000 400� <br /> �. S41LS(Sife evaluation data) <br /> 1. Depth to restricting lay�= 2.7 f�t <br /> 2 Depth af percotation tests= 12 indies <br /> 3. Texture loam <br /> 4. Soit loading rate(see Frgure D-33) 0.60 9P�� <br /> Percofation tafe 7 MPI <br /> 5. %Land Slops 8.0 % <br /> D. ROCK lAYER D1IRENSI��tS <br /> 1. Multiply average design flaa(A)by 0.83 b obtain required�ea oF rock lay�:ltem A x 0.83= <br /> �0 gpd x 0.83 ft�lgpd= 500 fl <br /> 2 Determine rock layer widlh =0.83 fl`/gpd x Lit�ear Lnad'�ng R�e(LL.R)(s�ee LLR chart <br /> 0.83 it�/gpd x t2.W = 40.0 ft <br /> LLR Chart <br /> Perk Rate LLR <br /> <12Q MPt <=12 <br /> >=120 MPI <� <br /> 3. Length of rodc laye.r=area dnrided by v�idth= <br /> 5OO.Q ft� / 10.0 feet= 50A ft <br /> E. ROCK VOLUME <br /> 1. Mul6ply toc�c atea by rodc depth to get cubic feet of rock <br /> 5�.0 X 1.0 ft= 500.0 ft <br /> 2. Divide ft3 by 27 fl�yd3 to ge#cubic yards . <br /> 500.0 fC� ! 27 = 18.5 yd3 <br /> 3. Mulbply cubic yards by 1.4 to get weight of rodc in tons; <br /> 98.5 yd3 X 1.4 ton/yd3 = 25.9 tons <br /> Page 1 of 5 <br />