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2000-P03410 - new septic
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1280 Lyman Avenue - 35-118-23-34-0014
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2000-P03410 - new septic
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Last modified
8/22/2023 4:59:10 PM
Creation date
6/26/2017 2:32:51 PM
Metadata
Fields
Template:
x Address Old
House Number
1280
Street Name
Lyman
Street Type
Avenue
Address
1280 Lyman Avenue
Document Type
Septic
PIN
3511823340014
Supplemental fields
ProcessedPID
Updated
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� <br /> G. DOWNSLOPE BERM WIDTH s'°a:- c�1' <br /> 1. If landslope is 1% or more .,,.:� .. <br /> subtract rock layer width from adsorption width ; : * �«� „,•'s ,: i <br /> to obtain m;�;*num downslope berm toe .:�a�s�,d � �e1c1 ' j� ' �� � <br /> �,�ft-11L ft=J�_feet atural So11 3�o _ 6�T°p�'' <br /> 2. Calculate Minimum mound Size �,wus�.o�• <br /> a. Determine depth of clean sand fill at �wa� D°''""S�""dm <br /> upslope edge of rock layer. � n ��wa�, <br /> Separation 3' - /•� ft= Z•� feet �'O _ <br /> 3�i� <br /> b. Add depth of clean sand for separation(2a) <br /> at upslope edge, depth of rock layer(1 foot)to depth of cover <br /> (1 foot) to find the mound height at the upslope edge of rock layer; <br /> -?��ft+'lft+ lft=�._feet <br /> c. Enter table with landslope and upslope berm . .:.�w;d�;�:. <br /> ratio. Select berm multiplier of . . ;; � , ,,,a^ � :. <br /> d. Multiply berm multiplier by upslope mound :;::�'"'d�' i'4i��'�"�"�� ��,.'.°�.,�►'���. �'�'°ne`"'a�n <br /> N w '�f VNidth ,Y P�.y�Pk�4 y -1�- <br /> height to find upslope berm width: '1(, � `������ �' ��'s�`�'���� <br /> T---�.-- feet s'Q ': ; , �F t, u�:j::;:,,�:�.::�.:n �(� t <br /> - - �i ��., � c c � . '� r f . i 3 :. <br /> e. M u l t ip ly roc k layer wi d t h by i :. .. . , : <br /> R . ., ,,:.� ��. . <br /> .. ,.�. , ... . <br /> .. ... . <br /> landslope to determine drop in elevation; ` <br /> �° , nov�+alope w� <br /> � Absorptl <br /> �x 3 %+ 100= - feet ± � <br /> f. Add depth of clean sand for slope <br /> � .� �'. ... .. �, :::= :.. �.. �. :�t,-;:. i :.. <br /> difference (2e)at downslope edge,to T���� <br /> the mound height at the upslope edge <br /> of rock layer (2b) to find the downslope height; <br /> ft+ ft= u , o feet <br /> g. Enter table with landslope and downslope berm ratio. Select <br /> berm multiplier of �t.S'� <br /> h. Multiply berm multiplier by downslope mound height to get <br /> downslope berm width: <br /> �i.S�I x 4.D =�_feet s�si.opE Mcn.��xs <br /> i. Compare the values of step G.1�.Z <br /> and Step G.2h�� i''aa eam��r�moo� �� ptl�°r�o�.�� <br /> Select the greater of the two values as the �� ����.e� e«���n� <br /> downslope berm width; 1 � feet <br /> j. Total mound width is the sum of � � � � � � � � � � � <br /> 0 3.0 4.0 S.0 6.0 �.0 3.0 4.0 S.0 6.0 7.0 8.0 <br /> upslope berm(G.ZGl� ( 3.09 4.17 5.26 6.38 �.53 2.91 3.85 4.76 5.66 6.54 7.41 <br /> width plus rock layer width(D.2� Z 3.19 4.35 5.56 6.82 8.14 2.83 3.70 4.54 536 6.14 6.90 <br /> plus downslope berm width(G.21�� 3 3.30 ..(4.54�? 3.88 7.32 8.86 2.75 3.57 4.35 S.O8 5.79 6.45 <br /> ,�.�_ft+ 1�) ft+.��ft= � ,�feet 4 3.41 4.76 6.25 7.89 9.72 2.68 3.45 4.17 4.84 5.46 6.06 <br /> k. Total mound length is the stun of upslope s a.ss s.00 6.67 ss� io.n z.6i 333 a.00 a.bz s.i9 s.�i <br /> berm width(G.2d)plus rock layer length(D.3) 6 3.66 s.26 �.ia 9.38 i�.m a.sa s.z3 3.ss a.ai 4.93 s.ai <br /> plus upslope berm width (G.2d�� � 3.80 S.S6 7.69 10.34 13.73 2.48 3.12 3.70 4.Z3 4.10 5.13 <br /> ,��ft+��ft+��ft= �_feet $ 3•95 3.88 833 1 t.34 t3.91 242 3.03 3.57 4.05 4.49 4.88 <br /> 9 4.t l 6.25 9.09 I3.04 t8.92 236 2.94 3.45 3.90 430 4.65 <br /> !0 4,29 6.67 10.00 15.00 13.33 2.31 2.86 3.33 3.75 4.12 4.44 <br /> Final Dimensions: 11 4.48 7.14 11.11 17.63 30.43 226 278 3.23 3.61 3.95 4.26 <br /> 12 4.69 '7.69 1230 21.43 43.75 2.21 2.70 3.12 3.49 3.80 4.08 <br /> �-I t� X � / <br />
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