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septoc onfo including 1990 septic design
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1220 Lyman Avenue - 35-118-23-34-0016
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septoc onfo including 1990 septic design
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Last modified
8/22/2023 4:59:18 PM
Creation date
6/26/2017 1:05:16 PM
Metadata
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Template:
x Address Old
House Number
1220
Street Name
Lyman
Street Type
Avenue
Address
1220 Lyman Avenue
Document Type
Septic
PIN
3511823340016
Supplemental fields
ProcessedPID
Updated
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� . , E-ly <br /> , • ' MOUND DESIGN WORK5HEET � " <br /> �• ' � (For Flows up to 1200 gpd) � <br /> A. FLOW �� D-7 .:: ; ;� . <br /> . � <br /> Estimated G,00 gpd (see pages D•7 or I-3,4,5) a^�►^m R�..M�,�,�� <br /> trrt o►an�eiwc��"'� <br /> or measured — gpd. � � o � <br /> • � ! 700 b! .t�0 �dL <br /> � � �� MO 100 tl� �� <br /> 1 • � �00 � Yf w; <br /> B. SEPTIC TANK LIQUID VOLUMES � �� � � <br /> .�- J o 0 o gallons (see pages C-3 or C-5) • � �� •n �« �- <br /> C-3 � <br /> C. SC�ILS (refer to site evaluation) ' •�•*�. �C�AC1T1[s.�M QAl1.ON� <br /> 1. Depth to restricting layer= I� inches �« � � <br /> 01001M N011O W�CfI► �IMM1l <br /> 2. Depth of percolation tests = 1 z lItCtIES �a„� ��� ���� <br /> 3. Percolation rate 1 g .f mpi •«�� ,N. ��.� <br /> 4. Land slope_ � °7n % <br /> ��. ,... ���. <br /> �,.�. ..�. .... <br /> D. ROCK LAYER DIMENSIONS -• <br /> � 1. Multiply flow rate by 0.83 to obtain required_area of rock <br /> layer: A x 0.83 = <br /> �c�o gpd x 0.83 sq. ft./gpd =��sq. ft.-�-I o°)v Sy 7 <br /> 2. Se:ect width of rock layer (10 feet or less) = i o ft. <br /> • 3. Length of rock layer = area j width= • <br /> 5 y'� sq. ft. i �_ft. _��ft. Rock Bed <br /> � l•f t•f I'\l./'•'�l7f7f7f•1• I•f <br /> . ti�ti.L.�.ti.{� • <br /> .r.r.f.r.r r?i?�7��r�i�}:i?r7F <br /> ti.ti.ti.ti.ti.� ti•�•}•ti.ti•ti.ti.ti.ti• dth S10tt. <br /> . t�t•f•1•t•f•1•f t�!•I•1•t•!•�� <br /> ♦�ti���ti�'L�1�ti���tiH�ti�ti�ti•�•ti <br /> E. ROCK VOLUME •�•�_ �ng�'r•r•r.�.r.} <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> S 47 sq. ft. x�ft. _��cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> , �y cu. f t. +27= a� cu. yd. � <br /> 3. MulHply cubic yards by 1.4 to get weight of rock in tons, <br /> �cu. yd. x 1.4 ton/cu. yd. =�tons. • . <br /> F. ADSORPTION WIDTH � <br /> 1. Percolation rate in top 12 inches of soil is /q./ mpi E-16 ` <br /> 2. Select allowable soil loading rate from table on page E-16; •�••••��•••••••�•••�•.�..M�•» <br /> __� gpd/ft2 <br /> , ,�..,. ;�..,.,.,..r.. �.�.�.,... <br /> 3. Calculate adsorption width ratio by dividing rock layer """" """ """ """ `""`""'" <br /> . �.1• � t.N tM •.M �.N <br /> loadin� cate of 1.20 gpd/ft2 by allowable soil loading rate; . ' •�• •°� ��N ��, ��► <br /> ,. ... ..« .... �.. �» <br /> �� .�� �.w �a �a �..� <br /> • 1.20 gpd/ftz+�gpd/ft2= a, o .. ... .... .,. ,... .... <br /> �1 .IN �.�� RN �.N RM <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; ' � ' <br /> �,v x J� ft =,��ft • <br />
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