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� � ' ` �'UMP SELECTIOI�T�P�Z�C�D�JRE 'C''Sv�P �a <br /> 1. Determine pump capacity: <br /> ;R-m..�A. Gra�ity distribution <br /> 1. Minimum required discharge is 10 gpm . <br /> 2. Maximum suggested discharge is 45 gpm. For other <br /> establishments at.least 10%:greater than the water supply rate, <br /> b�at no faster than the rate at which effluent will flow out of the <br /> disttibution device. � . <br /> B. Pressure distribution <br /> See pressure distribution work sheet <br /> From A or B.�elected'pump capacity: �_gpm <br /> 2. Determine pump head requirements: <br /> A. Elevation difference between pump and point of discharge? sofl treatment system <br /> &p ( t of discharge <br /> _�_feet =�� in c�. o <br /> B. Special head requiremerit?(See Figure at right-Special Head Requirements) �� �F� <br /> =feet 2A,elevaflon <br /> (nlet difference <br /> C. Calculate Friction loss p�� <br /> 1. Select pipe diame#er in ...`_ -------------------------- ------. '�Z�c� <br /> 2. Enter Figure E-9 with gpm(lA or B)and pipe diameter(Cl). <br /> Read friction loss in feet per 100 feet from Figure E-9 Special Head Requirements <br /> Friction L:oss=��3_�/100ft of pipe Gravity Distribution 0 ft <br /> 3. Determine total p�pe length from pump discharge to soil treatment Pressure Distribution 5 ft <br /> discharge point.Estunate by adding 25 percent to pipe length for <br /> fitting loss.Total pipe length times 1.25=equivalent pipe length E-9: Friction Loss in Plcstic Ptpe <br /> �i S feet x 1.25 = S(o feet Per 100 feet <br /> 4.CaTculate total firiction loss by multiplying friction loss (C2) nominal <br /> in ft/100 ft,by:.the equivalen#pipe length(C3) and divide by 100. flow rate �,y��pe dZamete3n <br /> - 4 . � ft/100ft x�_+100= � ft m <br /> ' D. Total head required is the sum of elevation difference(A�,special � 2.47 0.73 0.11 <br /> head requirements.($),and total friction loss (C4) 25 3.73 1.11 OJ 6 <br /> _,�_ft+ , s ft+�_ft= 30 5.23 1.55 0.23 <br /> 35 6.96 2,06 0.30 <br /> Total head: o feet ao s.9t 2.ba o.39 <br /> 3. Purnp selection a5 >>.07 s.2s o.as <br /> 50 13.46 3.99 0.58 <br /> . 55 _ 4J6 0.70 <br /> A purnp must be selected to deliver at ieast�nt 60 � b.60 0.82 <br /> (lA or B)with at least._1�2,_feet of total head (2D) � 6.48 0.95 <br /> 70 7.44 1.09 <br /> 1 hereby certify that I ha e completed.this work in accordance with agplicable ordinances, :rules and laws. <br /> �� . � � (signature) 3�7�{ � . (license#) �-�S-O� (date) <br />