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1998-010869 - septic system
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1998-010869 - septic system
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Last modified
8/22/2023 4:59:40 PM
Creation date
6/22/2017 1:08:10 PM
Metadata
Fields
Template:
x Address Old
House Number
1170
Street Name
Lyman
Street Type
Avenue
Address
1170 Lyman Avenue
Document Type
Septic
PIN
3511823430028
Supplemental fields
ProcessedPID
Updated
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' ' t-ly <br /> ' MOUND DESiG1�1 WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW D-� � <br /> `% `� - FSi�W1ED S(YNG(RO'MS iN G►LLDNS►Q J�r <br /> Estimated gpd (see pages D-7 or I-3,4, 5) <br /> H�EA TrPI Of RlSiOEMCE° <br /> or measured gpd. �°"°°'6 ' ° a s <br /> = JOO 72� ��0 i01 <br /> 3 •]o b0 21� er <br /> � soo �n tsc <br /> B. SEPTIC TANK LIQLJID VOLLTMES * � � � `'�` <br /> -� � _ gallons (see pages C-3 or C-5) ° 12Oo °�° � ��- <br /> C-3 <br /> C. SOILS (refer to site evaluation) SEOT�� T�NK CAVACITES, �N GALLONS <br /> uowo c•o•cm <br /> 1. Depth to restricting layer = <';�"� inches ""'"' ��� �°.�.°• <br /> �meoaw uoum w.an oisroa�� <br /> 2. Depth of percolaHon tests = ' -� inches ,�,,,,. ,,, ,,,, <br /> 3. Percolation rate � mpi �°�� �••� ,s•� <br /> 4. Land slope °'o ��� ���� "" <br /> ,.,�. ..oa �.ao <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> ,.� ��� __ gpd x 0.83 sq. ft./gpd = sq. ft. <br /> 2. Select width of rock layer (10 feet or less) _ ' ' ft. <br /> 3. Length of rock layer= area i width = Rak Bed I <br /> ' '_sq. ft.y _ ' ft. _ `. ft. <br /> ;.. <br /> �l�f•r•r•r•J•!•f•1�I•f•t•J•!•t � <br /> .,.�.�.�.�.�.�.�.�.�.�.�.�.�. T <br /> ti:��ti�ftif{��f�rti�ti�tirti:tirti�tif idth 51� � <br /> �r•l.r•r•f.l.r.l•r�l.l.l•1•f•t <br /> •�•�•�•�•�•�•�•�������������• 1 <br /> .f.f.�.j.f.�.r.f.d.f.f./.f.f•r <br /> E. ROCK VOLUME f-- Length --� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> -, -: �: sq. ft. x ' ft. _ ' �'cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> _-^'' cu. ft. i 27= �� cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; I <br /> �'�; cu. yd. x 1.4 ton/cu. yd. = i; �. tons. � <br /> F. ADSORPTION WIDTH I <br /> 1. Percolation rate in top 12 inches of soil is :� ' mpi E-16 <br /> 2. Select allowable soi� loading rate from table on page E-16� �++o��u�uc.n�.ma�ouu.ourcu.os � <br /> �d�f� :.��.� .�...�...�.`J � <br /> �+�M N�T� NO�� �Yt �~�n�rM <br /> 3. Calculate adsorption width ratio by dividing rock layer ' � <br /> �.�� � �.ae �.sa �.a �.00 <br /> laading rate of 1.20 gpd/ft2 by allowable soil loading rate; ' " °" ''. ," "' <br /> ,. ,a .w a.. .... ..oa ' <br /> �� .u e.w e.w e eo i..o <br /> l.z� gp�i/ft2�- ��gPd/ft2 = , ,.., ��, .. ..e o... e.,, ,., ,., <br /> �� -�te o.f� oA� �.0 �oo <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rnck layer width to get <br /> required adsorption width; ; <br /> 'r x 7 ft — ft <br /> � <br />
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