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, , �ir�I2f Sc�� S s.�-i <br /> � � MOUND DESIGN WORKSHEET � � <br /> (r�or Flows up to 120o gpd> <br /> A. FLOW �,�ea s�.�.g����a,i�:�n,r(�) <br /> Estimated�gpd N,.�� <br /> or measured x 1.5 = gpd. B�°�,,,, �'p`� �`° �'a1° �'a�� <br /> 2 3W 273 180 � <br /> B. SEPTIC TANK LIQUID VOLUMES ; bo i°s° isb ,� <br /> � � i D allons s �so .so 2�. ,� <br /> o----�g 6 90o su 332 � <br /> � �aso boo 3�0 �,.m,. <br /> 8 1200 675 108 <br /> C. SOILS (refer to site evaluadon) N�� <br /> µ� �w <br /> 1. Depth to restricting layer = v� inches °� � � <br /> B`m°°� � <br /> 2. Depth of permlation tests = 12 inches <br /> 3. Percolation rate I 2— 1 (� mpi z a� �so �.iu <br /> s«6 i'��oo �z.z�so <br /> 4. Land slope �_% ,a a z000 s.000 <br /> �tr 9 s«r�.c-� cx is� <br /> D. ROCK LAYER DIMETVSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required azea of rock <br /> layer:A x 0.83 = <br /> ��(L gpd x 0.83 sq. ft./gpd = � sq. ft. <br /> 2 Select width of rock layer(10 feet or less) _ �C� {t, <br /> 3. Length of rock layer=area=width = <br /> ���sq. ft.i !0 ft. = 38 ft. Rock Bed <br /> ti ti.�1��ti•t•Yti.t��•M�.��MS <br /> 1 1.1K•f�1•�l�yf•l•�'•1'•f•t•f• <br /> ti•L•ti.�K•ML�MwtiK•ti•Y1.�ti•M� <br /> ��j t•�ti•ti.tiK•M~Y��ti•Mti�M��� idth <_10 ft. <br /> f•1•lN�t•1•Mr�lMN'�fY��H1 <br /> ~1�1�r rKKfYN��f fK�MI'�~h��M <br /> E. ROCK VOLUME � �� <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; <br /> 3�sQ•ft.x � ft. _�cu. ft. <br /> 2. Divide cu.ft.by 27 cu.ft./cu. yd. to get cubic yards; <br /> �cu.f� i 27=�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu.yd.x 1.4 ton/cu. yd. _�tons. <br /> F. ADSORPTION WIDTH . �� . . � <br /> 1. Perrnlation rate in top 12 inches of soil is t�3D mpi P�„�,,,h�,R„� �. „�,� <br /> ����, Soil Texttue �� �� <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 rse Sand l�o l.00 <br /> D-6 gpd/ft2 o.t to5 Sand t.2o 1.00 <br /> 0_1 to 5 Fine Sand" �-6�1 2•00 <br /> 6 to 15 ndy Loam 0.79 132 <br /> 3. Calculate adsorption width ratio by dividing rock layer 3—�-� Silt Loam o-so 2-ao <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to 6o cta�[.oaa► o.4s 2.6� <br /> 1.20 d/ftz-�- d/ft�= O 61 t0120 y osa s.00 <br /> � ��� �• Slower than 120 Cla — — <br /> "Sail having 509G ar maer of fuie ar very Curc aand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �.�x��ft =� ft <br />