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2000-P03411 - new septic
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1150 Lyman Avenue - 35-118-23-43-0029
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2000-P03411 - new septic
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Last modified
8/22/2023 4:59:41 PM
Creation date
6/22/2017 12:55:48 PM
Metadata
Fields
Template:
x Address Old
House Number
1150
Street Name
Lyman
Street Type
Avenue
Address
1150 Lyman Avenue
Document Type
Septic
PIN
3511823430029
Supplemental fields
ProcessedPID
Updated
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���/ s,`'� <br /> • . � . MOUND DESIGN WORKSHEET <br /> (i�c�r Flows up to 120O ����i) <br /> A. �'vW Estimated Sew�gc Flov in(idlant per D�y(Q�) <br /> Estimated _��gpd N�,� <br /> or measured x 1.5 = �,d. °� �' �° �'a�T� iYa rv <br /> - �� «�m�m. <br /> z 30o zu ieo �,,, <br /> B Sr-.PT7C TANK LIQUID VOLIJMES ; � ;°� 2� � <br /> s �so �so Z9� •''"`. <br /> g��� 6 900 525 332 u� <br /> 7 1Q50 600 370 s0i� <br /> S 1200 675 �OB `°�`m" <br /> C. SOILS (refer to site evaluadon) <br /> 1. Depth to restricting layer = � �( inches N�� � a-�• <br /> r�. c+v�,... <br /> 2. Depth of peroolation tests = _ !2 inches �� `'""' '� <br /> 3. Percolation rate mpi ��P►�. 2s«aa �'.oso°o i''wuo <br /> -�l 4. Land slope � % s a 6 �.soo zzw <br /> �a s z000 3.000 <br /> wc 9 See!g.C� (x 1.5) <br /> D. ROCK LAYER DIMIIVSIONS <br /> 1_ Multiply flow rate by 0.83 to obtain required area of rocic <br /> layer:A x 0.83= <br /> �_gpd x 0.83 sq.ft./gpd =�sq.ft. - <br /> 2. Select width of rock layer(10 feet or less) _�y�{f, <br /> 3. Length of rock layer-area=width = Rock Bed <br /> �sq. ft.1 7 ft. _ �$' ft. ti.ti.ti.,...�...�.�.ti...�-�.�.ti.... <br /> S � 1.1.1Y�J.f.t.t•l l.hl'•f•f•l•l• <br /> ti•ti•ti•tiK.���•MYtK�tKN.��K�� <br /> y• l.J•f.H1•1.1M�tM.f�h1'w•f•1• <br /> ti•�.ti.�.ti-ti.�.ti.�•ti.ti.� idth SIO ft. <br /> 'ftiw.�:ti'r'.,,.�'ti.ti�.�'.ti•ti.ti.ti.ti.ti <br /> •t•t•f.lK•hh t•1•I•f•1��J•l� <br /> E. ROCK VOLUME f t,e�grh <br /> 1. Multiply rock area by rock dep�h to get cubic feet of rock; <br /> sq.ft.x ft. = cu. ft. <br /> 2. Divide c�ft.by 27 cu.ft./cu. yd. to get cubic yards; <br /> cu.ft. -:-27=-�_cu_ yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> cu.yd x I.4 ton/cu.yd. = 2.���, <br /> F. ADSORPITON WIDTH <br /> � rr�ad� � • r�k <br /> 1. Permlation rate in top 12 inches of soil is3�/c� i <br /> � �O6 r.pT ��� so�1 Taaure � �r <br /> 2• Select allowable soil loading rate from'table; � <br /> Faster than 0.1 rse Sand 120 1.00 <br /> .Z gpd/f t2 o.t co s Sand 12(1 1.00 <br /> 0.1 to 5 Fine Sand"' �-bq Z-00 <br /> 6 to 15 ndy Loam 0.79 1S2 <br /> 3. Calculate adsorption width ratio by dividin rock la er tb co 30 [,oam o.bo 2•00 <br /> g y 31 to 45 Silt Loam �� 2•'� <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to 6o cta [.oam o.45 2.6� <br /> 1.20 gpd/ft2y�.z�BPd�ft� = S•� _. 61 co i2o ��y o2a s_oo <br /> Slower than 120 Cla <br /> "scil having sox Q mae ot 6.�e ar vey Gne�ana. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> 5.0 x_�ft = �S ft <br />
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