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2000-P03411 - new septic
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1150 Lyman Avenue - 35-118-23-43-0029
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2000-P03411 - new septic
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Last modified
8/22/2023 4:59:41 PM
Creation date
6/22/2017 12:55:48 PM
Metadata
Fields
Template:
x Address Old
House Number
1150
Street Name
Lyman
Street Type
Avenue
Address
1150 Lyman Avenue
Document Type
Septic
PIN
3511823430029
Supplemental fields
ProcessedPID
Updated
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� PRESSURE DISTRIBUTION �vS'rFM Geotextile fabric <br /> 1. Select number of perforated laterals .3 = '�� � <br /> uarter inch doradons s aced�3' 2�� ' <br /> 2. Select perforation spacing = �_ feet. 9"of mck <br /> 3. Since perforations should not be placed closer than 1 Et. to Perf Sizing 7/32"-1/4" <br /> Perf Spac�ng 1.5'-5' <br /> the edge of the rock layer (see diagram), subtract 2 ft. from <br /> the rock layer length. <br /> Rock la— ye�T i� - 2 ft. _� feet. <br /> RequireA PerloraUcm D�sclurFr <br /> 4. Determine the number of spaces between }�erforations. ,,,F•���Ms,x•�m,���,•�dv�,, <br /> Divide the length above by perforation spacing and round �g` �,�� ;,�,� <br /> down to nearest whole number. "`"' <br /> 1.Oa 0.56 0.74 <br /> Length perf. spacing = � ft. =�ft. _�2-- spaces <br /> 2.Ob 0.80 1.04 <br /> �3� �2� a.Use for single family homes <br /> b.Use for all other applications <br /> 5. Number of perforations is equal to one plus the number of <br /> perforation spaces . <br /> �� spaces + 1 - I 3 p Maximum number of quarter inch perforations pe <br /> - erforations/lateral lateral to guamantee<10°/a discharge variation <br /> Perforation <br /> 6. Multiply perforations per lateral by number of laterals to S�f�tjg j% ly 2 <br /> get total number of perforations. 2,5 14 I8 2$ <br /> ��,5 x � -�perforations. 3.0 � 17 26 <br /> �"��' 3.3 12 16 25 <br /> 7. Determine required flow rate by multiplying 4.0 11 IJr 23 <br /> number of perforations by flow per perforation 5.� 1Q 14 22 <br /> �— X •� " _�� IIl. wun�mo wurco�r o0 oF v�sa�on�aieuraN srsreM <br /> Pe� 8Pm/ped gP <br /> .�" <br /> 8. If laterals are connected to header pipe as shown on upper � <br /> example, to select minimum required lateral diameter;enter i�,; � <br /> table with perforation spacing and number of perforations �- ,,,�•�'m'�'� .'""-' <br /> per lateral. Select mini, um diameter for ��_��"`" <br /> perforated lateral =� inches. <br /> 1��0ui M IEIKON�fEO Mf L�TEMLS fW� <br /> MESSIINC dSfp�MITlp1 M Y01/M <br /> RM'OYim I�py�K/I( <br /> 9. If perforated lateral system is attached to manifold i e near Y�«`��`�� M""�� ` <br /> PP r�� �/ <br /> the center, lower diagram, perforated lateral length and ..-�.,�..».�> <br /> n�srK raa <br /> number of perforations per lateral will be approximately one `�� ' �•-- •.,�.,,K;�; <br /> half of that in step 8. Using these val s, select minimum C�., b , <br /> � <br /> diameter for perforated lateral = � inches. ,�"`"` �,,.�,;�. <br /> < . <br /> �.�.��"' <br />
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