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��µ< . <br /> OSTP Mound Des�gn LJNIVERSITY <br /> Minnesots Pollution Worksheet OF MINNESOTA '='�:� <br /> Corrtrol Agency <br /> 1. SYSTEM SIZING: <br /> A. Design Flow(Design Summory fA): 75O GPD T��E <br /> MOUND CONTOUR LOAdiNG RATES: <br /> B. Soi!Loading Rate (Design Sum.2D): 0.60 GPD/ft2 �wrad � jo�ro �� Contour <br /> C. Depth to Limitinq Condition: 2.0 ft P°�`��° � "���O`P�"`� Rato� <br /> D. Percent Land Slope (Design Sum. 2B): 11.0 % s 64mpi �.o, �.a.z.o,z.a.Z.e -. <_i2 <br /> E. Design Media Looding Rate: 1.2 GPD/ftZ 61-120 mpi oR 5.0 <�z <br /> F. Mound Absorption Ratio: 2.4 >120 mpi .s.o° <_s• <br /> G. Design Contour Loading Rnte: 12 GPD/ft •Systems with these values are not Type I systems. <br /> (From Design Summary 2E-same as Linear Loading Rate) Contour Loading Rate is a recommended value. <br /> 2. DISPERSAL MEDIA SIZING <br /> A. Calculate Required Dispersal Bed Area:Design F(ow (1.A)=Design Media Looding Rate (1.E)=ftZ <br /> If a larger dispersal media 750 GPD= 1.2 GPD/ft2 = 625.0 ftZ <br /> area is desired, enter size: �ft2 <br /> B. Calculate Dispersa(Bed Width: Contour Loading Rate (1.G)=Design Media Loading Rate (1.E)=Bed Width <br /> 12 ft = 1.2 gpd/ft2 = 10.0 <br /> C. Calculate Dispersa!Bed Length: Dispersal Bed Area (2.A):Bed Width (2.6)=Bed Length - <br /> 625.0 ftZ = 10.0 ft = 62.5 ft <br /> D. Select Dispersal Medio: RoCk <br /> 3• ABSORPTION AREA SIZING <br /> Note:Mound setbacks are meosured from the Absorption Area. <br /> A. Calculate Absorption Width:Bed Width (2.6)X Mound Absorption Ratio (1.F)=Absorption Width <br /> 10.0 ft x 2.40 = 24.0 ft <br /> B. For slopes from 0 to 1%, the Absorption Width is measured from the bed equally in both directions. <br /> Calculate Absorption Width Beyond the Bed:Absorption Width (3.A)-Bed Width (2.6)=2=Width beyond Bed <br /> ( N/A ft - N/A ft) = N/A = N/A ft <br /> C. For slopes>1%, the Absorption Width is measured downhill from the upslope edge of the 8ed. <br /> Calculate Downslope Absorption Width:Absorption Width (3.A)-Bed Width (2.6)=ft <br /> 24.0 ft - 10.0 ft = 14.0 ft <br /> Comments: <br /> S(ope, CLR Choice, Materia!issues <br />