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2004-P07433 - new septic
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525 Leaf Street - 05-117-23-41-0020
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2004-P07433 - new septic
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Last modified
8/22/2023 5:21:43 PM
Creation date
5/3/2017 1:21:04 PM
Metadata
Fields
Template:
x Address Old
House Number
525
Street Name
Leaf
Street Type
Street
Address
525 Leaf St
Document Type
Septic
PIN
0511723410020
Supplemental fields
ProcessedPID
Updated
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1 .� �. . <br /> PRESSURE DISTRIBUTION SYSTEM Geotext�le fa�rtc <br /> . • �,. � ::�= <br /> 1. Select numbe�'of perforated laterals :5 . ��c� erto�non� eted m,3' " �'' '. <br /> � ��� -r:�'�>;.���. �-�;� ,. :.: .�;.�: . <br /> . . ' . . . n;'��... ..:���•:�,'• r' . . <br /> 2. Select perforation spacing=�_ft �. : ��..'��.'�,.�`"�t `.�.:r���� . .. . <br /> :�, �, �• �,,� <br /> � � Perf 3/16"-1/4" <br /> 3. Since perforations should not be�placed closer than 1 foot to p���S 1.�•-5' � <br /> the edge of the rock layer(see diagram),subtract 2 feet from . <br /> the roCk layer leagth. E-4: Maxhrx�m adowable number of 1/4inch perforation <br /> ' • . . per laterai b quarantee<10X c�acharge vodaHon <br /> � r -2 ft =�_ft� pertoranon � <br /> 4. Determine the nunlber of spaces between perforations. ��� <br /> � Divide the length G3)bY Perforation spacing C2)and t4iitlsl 1 Inch � :1.25 inch .i�:sinch� 2.o t�c�ro <br /> �to nearest�vhole number.. � � � ' 8 �14 18 � aA <br /> Perforation spacing= �s.�.ft+ 3 . ft=.1�3 sPaces � 3,0 8 13 t 7 � ?� <br /> 5. Number of perforations is equal to one plus the number of 3.3 > >2 �6 ( ��. <br /> perforation spaces(4)..Check�gure E-4 to assure the number of �4A 7 11 15 23 <br /> Pe�forations per lat�ral guarantees<10%discharge variation. 5A 6 10 t4 22 <br /> �Sp8Ce3+1 =��P�'fOrStiOnS/13teral E-6: Porforction Diacharge In gpm <br /> 6. A. Total number of perforations= perforatiQns per l�t�ral(5) perforation diomete� <br /> iisnes number of lat�erals.(1) head inches <br /> (feet) 3/16 7/32 1/� <br /> 1 /latx.3� '1at= �'Zi perforations 1.Oa 0.42 0.56 0.`?4 <br /> B. Calculate the square footage per Perforatlon. 2.Ob 0.59 0.80 �1. � <br /> Should be 6-10 sqft/perf.Does not apply to at grades. � <br /> Rock bed area= rock width(ft)x rock length(ft) 5.0 0.94 1.26 1.b5 <br /> . __1s2_�t x �-►. I ft=�L.��qft . � a u��a roor ro��,c��-fomn,,n��f <br /> Square foot per perforation=Rock bed area+nwnber of perfs (6) . b u� . s� o� i� e�so ;�� <br /> �l� sqft+.�?— perfs=.�'Z�qft/P� � �.T��a.� �.��.•,� .,;,.. . <br /> 7. Determine iequired flow rate by ntultiplying the total nwnber of , <br /> perforations.(6A) .by flow per perforation(see figure E-6) � � � <br /> lly`��a. � �, <br /> �Z " perfs x �� m/perfs=�_gpm <br /> . <br /> 8. If laterals are conriected fio header pipe as shown on upper �,,,,��; <br /> e7cample,to select nvriintum requi=ed lateral diameter;enter �„,�^""" <br /> figure E-4 with perforation spacing(2)and number of perforations �/ <br /> per lateral(5) Selectminimum�diameter for <br /> �niu�wt a�t�wrt�wTi ouwuo ro� <br /> perforated lateral= inches. <br /> ....�..�..,K..� <br /> 9. If perforated lateral system is attached to manifold pipe near � � •�' <br /> the center,lower diagram,.perforated lateral length(3)and ���f� ' „�, <br /> � . <br /> nuaiber of perforations per lateral(5)will be approxirriately one ���•�.• � <br /> half of that in step 8. Using�the�e values,select minimum - .,�,� <br /> diameter for perforated lateral= ��1 Z inches. �,w �, <br /> . . . . . �,,,,,,,�.��~` �.... . <br /> . .� ' <br /> ' . <br /> I hereby certify that�I have completed this work in acmrdance with applicable ordinances, rules and laws. <br /> v!�.� I L. '�7 � - /,.i......a...a\ c��� lliranan#� / � � !V � (date) <br />
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