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2003-P06971 - new septic system
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2003-P06971 - new septic system
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Last modified
8/22/2023 5:10:28 PM
Creation date
5/2/2017 1:43:39 PM
Metadata
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Template:
x Address Old
House Number
380
Street Name
Leaf
Street Type
Street
Address
380 Leaf St
Document Type
Septic
PIN
0411723230027
Supplemental fields
ProcessedPID
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� NZOUl`�JD DESIGN WORK SHEET(For Flows u to 1200 d) <br /> A. Average Design FLOW A-1: Estimated Sewage Flows in Gallons per Day <br /> num er o <br /> Estimated �So gpd (see figure A-1) bedrooms ciass� ciass u c�ass ui ciass iv <br /> or measured x 1.5 (safety factor) = gpd 2 � 225 �So � <br /> ,,�,.:.,,;,�, 3 - 450 300 218 of the <br /> 4 600 375 256 values <br /> B. SEPTIC TANK Capacity � >�-A��,,..,:,,,,�. 5 750 �0 294 in the <br /> ��+_��% ���,l�� 6 900 525 332 Class I, <br /> ��.Su � > on c� allons (see ure C-1) � ��� � s7o ii, or ui <br /> g �g 8 12U0 675 408 columns. <br /> f���'�'P��-�� <br /> C. SOILS (refer to site evaluation) 5��� �,•o'��,.) � 1 a.d70 Gl: Se ticTankCa acitiesfm allons <br /> Number of Minimum Li uid Li uid ca � W�� L'9uid capacity <br /> 9 9 P�ry with disposal& <br /> 1. Depth to restricting layer = 1.4� �0 a•5� feet Bedrooms Capacity garbage disposal ►�ft inside <br /> 2. Depth of percolation tests = /- n feet z o�ieu �so ltu Isoo <br /> 3. Texture Lt-A--� t�xkv✓1 3a�a �000 �soo Z000 <br /> 5 or6 I500 2250 3� <br /> Percolation rate �V�'� IriPI 7,8 or 9 2000 3000 <br /> 4. Soil loading rate .4 S �pd/sqft (see figure D-33) <br /> 5. Percent land slope 7 % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow (A) by 0.83 to obtain required rock layer area. <br /> �S� gpd x 0.83 sqft/gpd = coa� sqft <br /> 2. Determine rock layer width = 0.83 sqft/gpd x linear Loading Rate (LLR <br /> 0.83 sqft/gpd x 1� gpd/sqft= 1 o ft M ou nd LLR <br /> 3. Length of rock layer = area =width = <br /> .�a�.sqft (Dl) = �2c _ft (D2) _ ��ft G � 2O M PI < � 2 <br /> E. ROCK VOLUME > 120 M PI < 6 <br /> 1. Multiply rock area (D1) by rock depth of 1 ft to get cubic feet of rock <br /> a"� sqft x 1 ft = (o�, cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> (oa cuft = 27 cuyd/cuft =,�_cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons <br /> �cuyd x 1.4 ton/cuyd = �_tons <br /> D-33: Absorptlon Width Sizing Table <br /> F. SEWAGE ABSOIZPTION WIDTH Percol�tionRate LoedingRate <br /> in Minutes per Soil Textwe Gallons Absorption <br /> Inch per day per Ratio <br /> MPI uarc foot <br /> Fester then S Coerse Su�d 1.20 1.00 <br /> Medium Sand <br /> Absorption width equals absorption ratio (See Figure D-33) , �•mys°"d <br /> times rock la er width (D2) 16 to 30 � o.� z.� <br /> y 3t�o as su Lo.�,� o.so z.ao <br /> p�� x�Q_ft —�Z ft 46 to 60 S'and CClry�m 0.45 2.67 <br /> 61 to 120 Sitty Clay 0.24 5.00 <br /> Sandy Clay <br /> le <br /> Slowerthan 120• <br /> •Sy�em duigned(or Ibese�oils rtam be aber or perfomaoce <br />
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