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OSTP Pressure Distribution <br /> Minnesota Pollution • UN I V ERS[TY � - <br /> C o n t r o l A g e n c y Des�gn Worksheet OF MINNESOTA � ,��� <br /> 1. Select Number of Perforated Latera(s in system/zone: 3 CiQO� <br /> ��p���1,�° ���' Minimum� 4��� <br /> (2 feet is minimum and 3 fee[is maximum spocing) G A'perforatians spaced 3'apart 2'of rock <br /> 2. Select Perforation Spacing: 3.0 ft � 1z� <br /> ������ca�n�n� �. s������ <br /> o�o����o�� 9"ofrock'�o��o��b�o��s�a �o <br /> _o`oo'�o��o'i�"po or' �� s'o' oCEio`7u�"-�Sd' <br /> 3. Select Perforation Diameter Size 7�32 1n�h per�ora[ion sliing'h'[o Y" <br /> Perforation acin :2'ro 3' <br /> 4. Length of Laterals =Media Bed Length-2 Feet. Perforatfon can not be closer then 1 foot jrom edge. v 11.05.31 <br /> 63 - 2ft = 61 ft <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Laterals (Line 4)by the Perforotion Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 61 ft .- �ft = 20 Spaces <br /> 6. Number of Perjorations per Lateral is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforotforrs Per Lateral = 20 Spaces + t = 21 Perfs. Per Lateral <br /> Check tvbfe below to verijy the number of perforations per(ateral guarantees less thvn a f0%discharge variotion. The votue is <br /> double if the a center rtwnifo(d is used. <br /> Maximum Numbe�of Perfaratiom Prr t.strral to GauraMev<70%D'escharge Variation <br /> ',Inc P orationz 7l32 Inch Pc'io�aciorx <br /> Pipe Diartfetcr tlrxhesy Perforatio�Spacing Pipe Diameter(4ncF.es> <br /> Perforation Spscing(Fce[) <br /> t tiE 7vz 2 3 lFeetl 1 7S4 tv: 2 3 <br /> 2 10 13 1a 30 60 2 1/ 76 21 3a 68 <br /> 2t� 8 12 16 28 54 2r 10 1a 20 32 64 ; <br /> 3 B 12 16 25 52 3 9 14 19 30 60 � <br /> 3%161nch Pe�rforaiiom 1:8 Inch Perforatio+u I <br /> PerFontion Spxing IFeet) Pipe Diametor(InchQzl Perforation Spxi�g Pipe P:ameter Iinchas) <br /> t �w 112 2 3 (FQet{ 1 tu f�4 2 3 � <br /> 2 1Z 18 2b 46 67 2 21 33 i4 74 144 <br /> 2tZ 72 17 2� 40 80 2v: 20 30 47 69 135 <br /> 3 12 16 22 37 TS 3 20 29 3a 6A 12E <br /> �- Tota[Number of Perforntrons equals the Number of Perforations per lateral (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 21 Pert. Per Lateral X �Number of Perf. Laterals = 63 Total Number of Perf. <br /> 8. Calculate the Square Feet per Perforation. Recommended value!s 4-f0 ft z per perforation. ""`°^"°"01di�'��GPMj <br /> Does not apply to At-Grades ,,,,,�„> '�``°`�"°�D1a�` <br /> ,,. ,,,. -,� ,,. <br /> Bed Area = Bed Width{ft)X Sed Length(ft) <br /> �.0 o.�s o.si o.0 o.ss <br /> 1.5 0.22 O.S1 0.6f O.! <br /> 10 rt x 63 ft = 630 ftZ i� a.x 0.59 a.p ,A. <br /> :.s o.r a.� a.n �.,� <br /> 3.0 0.32 0.72 O.f! 1.m <br /> Square Foot per Perforotion =Bed AreQ divided by the TotQ(Number of Perforntfons (Line 7). •.� �.» o.� ,.,� ,.•� <br /> S.0 0.�1 0.97 /.T6 1.65 <br /> Dwelli�s with J/t01rch to 1/s i�ch <br /> 630 tt2 .- 63 pertorations = 10.0 ft2/perforations '`°°` v�•�a.�� <br /> Dwelfl�s with�/8 irich perforat6i¢ <br /> 2 feec p�1xr eua0lhMnenn and MSTS wk�3/16 <br /> 9. Select Minimum Average Head: 1.0 fC Inc�to II11nc�D�No�atiom <br /> 5 feet aher estaMkhnents and N57S wit�t/6 inc� <br /> pertoratbm <br /> 10. Select Perforntion Dlscharge (GPM)based on Table III: 0.56 GPM per Perforation <br /> �1• Determine required F(ow Rate by multlptying the Tota!Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br /> 63 Perforations X 0.56 GPM per Pertoration = 36 GPM <br />