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��"` OSTP l�tound Des� n , . <br /> �� � v <br /> M��� UNI ERSITY <br /> �d�Y VI/orksheet �1% Stope dF MINI�TE�OTA ' �;,,�.;,,, <br /> L SYSTEM S1ZiNG: Project tD: v Ob.12.13 <br /> A. t)es;gn Ftow: 75o GPD Tl�l�E fX►a <br /> B. Soi[loading Rate: 0.45 GPDlft2 �o w►�s fae o�rpa��wu eor�r�erria��. <br /> A1D�1�►f�lt R�tTiEBS U�i P�►TION T�TS <br /> C. Depth to Limiting Condition: 1 Z ft � �'"'� �' <br /> � ""°M'"oA"a�' "°'°'w°" � 'Y�°�pY"' Me�we <br /> D. Percent Land Stope: 6.0 % � �,,,, � � � <br /> E. DesTgn AAedia Loading Rate: 1.2 �i �� <br /> �GPD/ft� �, _ . <br /> � � <br /> F. Mound Abwrptiot►Ratio: 2.b0 0'�s +.s � t.s � <br /> �w �ry,es«,e o.s 2 � 1.s <br /> ����16 RA�S.` td tS 0.78 1.6 1 t.t <br /> � '�' T�tiFp-dOPIMid t�OtlF 4e m 30 0.i II o.78 2 <br /> P+l�+t Nib � � lO�d�l� t ro 40 Q.S 2.4 0.78 2 <br /> '' i�lpC �6 ec AD O.�Ii �.8 O.i 2.� <br /> ��nP� 1.0. i.3,2.4.2.d.2.6 s12 �oo tzo . 6 O.a s.1 <br /> . �,so . _ <br /> 6�-�zo� � s.o s�� � � <br /> • "SYstems with these vatues are not Type t syscems. <br /> z yta mpa' >�.o• �a. Contour Laading Rate(tinear toadfn�rate)is a <br /> recommended va(ue. <br /> 2. DISPERSAL MEQIq StZING <br /> A. Calcutate Dispena!BerJ Area: �sign Ftow�Design Media loading Rate=ftz <br /> 750 GPO � f.2 GPD/ft2 = 625 ft2 <br /> tf a larger dispersel media area is desired,enter size:��ft� <br /> B. Ertter Dispersat Bed Wtdth: 10.Q ft Car�nvt exceed f0 feet <br /> C. Calcukate Contaur Loading Rate; ged yVidth X pesi�n Media Loadirr�Rate <br /> �� ft= X 1.2 �pp�ft2 s 12,0 ga!/ft Can not exceed Tabte t <br /> D. Catculate Minimum Dispersat 8ed LengLh; pispersa�gec}qrea f Bed Width =Bed Length <br /> 63� �t� .� 10.0 ft = 63A ft <br /> 3. ABSORPT'ION AREA SIZING <br /> A. Cattulate Absarption 1K'idth: ged yyidth X Mound A��ption Ratio =Absorptian Wicfth <br /> iQ.O ft X 2.b = 26.0 ft <br /> B. For slopes>1%, the Absorption Width is measured dqwnhfit from the upstope edge of the Bed. <br /> Calcutate Oawnstope Absorption yyidtf�;,4�Orptmn yVidth • ge,d Width <br /> 26.0 ft - 10.0 ft = 16.0 ft <br /> DISTRIBUT'ION MEDIA;ROCK <br /> A. Media Volume:Media Depth X Length X Width <br /> t.� ft X 63.0 ft X 90.0 ft= 634 ft3 + 27 = 23 y�3 <br />