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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Es�mmed Sewaee Flows m Gylon a v <br /> e d) <br /> Estimated 7S� gpd N„�,� �, �,� ��o � <br /> or measured x 1_5 = �,�d. �°°� ry <br /> ' 30o z±s I �ao � <br /> ; aso 300 ��e �u � <br /> B. SEPT'IC TANK LIQUID VOLUMES ' � 60D »5 '� a� <br /> � 5 750 a50 Zq� •y� I <br /> /S--r�''f, gallons—/ST?A��L /G���i4.�G/i�-��./p��,.,C, 1 i w 6o iio T��� ' <br /> ���� �/}GLO� '_'^+� 8 120D 675 �{ <br /> `+v�/ / ca mns <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer - s� � T�pkc� ��;�r;p ,,,,�5, <br /> - � inches ----f�- �w�,a��,��,;; <br /> 2 Depth of percol tion tests Z ��m��o� Mm�mum � <br /> — � inches Bedroo:ns � ��������"�� W��hd�sposali <br /> Gp�cny earb�ee d�sposal lifi ins�de <br /> 3. Textur Percolation rate�_ mpi ��a f= ,so ;,,; <br /> i000 1i0° <br /> 4. Land slo�e_��o ;ab ,� �;� '000 <br /> 7.8 or 9 Zppp � � <br /> z000 <br /> D. ROCK LAYER DIMENSIONS � <br /> l. Multiply flow rate by�to ob�ain required area of rock layer: A x 9�3-� Mound LLR <br /> SO �d X � ���d = So sq. ft. Perc Rate LLR <br /> 2. Determine width of rock layer = 0.�&�sq_ ft./gpd x Linear Loading Rate (LLR) �120 MPI < 12 <br /> �°�—A-�3 sq. ft/gpd x So = 7So ft >120 MPI S 6 <br /> 3. Length of rock layer= area = width = <br /> �sq. ft. - � ft. ,;-.� er... e*;>. ; -.:.:a_:.:..,.o,: .,. .a a b,,, <br /> _ ��ft_ o ��,;�• b.� , <br /> a �e•:r�':�sa,ro.�b o - <br /> Q.o��cS;�ax.•.e�eaA92" <br /> s e�•so�c�oao�drP �b <br /> Width /O ft �:.:.e:,o� �Q_ `�e. :, .e . <br /> e4. <br /> <120mpi <10' Lengthl�ft� <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�sq. ft. x_L ft. _ <br /> 7�cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu. ft. =27=�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;,�frcu. yd. x 1.4 ton/ <br /> F. ABSORPTION WIDTH <br /> l. Percolation rate in top 12 inches of soil is� mpi Absorplion�YidthSizingTable <br /> Texture R�co'w°^'tuei �a��ons R��oa <br /> �tinu�cs per IncA Soil Tcawrc rcrAa.�per AAso7vion rid�h <br /> (A1%) spmm fooi �o Rxk Laya <br /> WiE1h <br /> 2. Select allowable soil loading rate from table; Fu�er�Aan0.1 �„�S,b ,.20 ,� <br /> 0.1�0 5 Mcdium Sanf 1.20 I.OD <br /> � � LoamyS�nd � <br /> � �C�/ftz o.i�o s Fine SanO o.bo z.00 <br /> 6�o I S S�ndy(nam 0.79 I.S_ <br /> 16�o JO Lpam 0.60 I.W <br /> 71�o<5 Sih ldam 0.50 Z.aO <br /> SiY <br /> 3. Calculate absorption width ratio by dividing rock layer •6io60 "'s`°'�" °•S �.6' <br /> SanAy CL <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; s�o�°��;�°,� �;; ojo 6� <br /> 1.20 gpd/ft2 = (�.79 gPd/ft2 = . 5 Z . <br /> 4. Multiply absorption width ratio by rock layer width to get <br /> required absorption width; <br /> ����c /D ft =lS�'z-ft <br />