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MOUND DESIGN WORKSHEET <br /> � (For Flows up to 1200 gpd) <br /> A. FLOW Esumaud Sewa�e Flows�n Gylo�s p��d�y <br /> Estimated �.�(� � `'o, <br /> d N,�n�. c�i a�n c�io � <br /> or measured x 1.5 = �,-�d. �°'°�°^� N <br /> ' �ao zzs <br /> ; aw 70o I ?g rr�: <br /> B. SEPT'IC TANK LIQUID VOLUMES � `0° 35 '� '`"` + <br /> s 75o eso zq, •n� <br /> �-,�O _gall ns /Sr Ti4N� /O"G�J/�4��e�P 6 �oo su ,,, � , <br /> �`�7� � ioso 600 3� T��. <br /> /� `Z� 2N�T_ / 8 1200 67S apg � <br /> �L�� /�I�rl�r tolumnt <br /> C. SOILS (refer o site evaluation) <br /> 1. Depth to restricting layer = _ /Z feet � T�^kCa �;�;�r;. ,,,,�„ <br /> inches Lqwd.�,.�,:; <br /> 2 Depth of percolation tests = �Z •'�`�mbuoi Mm�mumLpud Gqudopxu�.w�� ai�hEisposais <br /> - 111Che$ Bcdroo:ns C�p�ci9' garbaee disposa! li(�mtnle <br /> 3. Texture L-�?r�'I Percolation rate Za rripi �30;SS �w ;,�; <br /> i000 �:� isoo <br /> 4_ Land slope�_% ;a6 ,� z,� �oo <br /> 7.8 or 9 2000 J000 �000 <br /> D. ROCK LAYER DIMENSION� <br /> 1. Multiply flow rate by 0:�}3-to o t�n required area of rock layer: A x$$� Mound LLR <br /> �gpd x sc�ft./gpd = sq. ft. Perc Rate LLR <br /> 2. Determine width of rock layer -�$3 sq. ft./gpd x Linear Loading Rate (LLR) �120 MPI S 12 <br /> ��$3-sq. ft/gpd x�_ _ ��p _ft >120 MPI <_ 6 <br /> 3. Len th of rock layer = area — width = <br /> _ � . .,,. <br /> +,�:e:..o:S•:: e+b�t.._.. . � r.:•�a:'.:.SQ. ae.o0.�.e:op ve.an.era�� . <br /> sq. ft. = �_ ft. ft. o, .::...p�� •.b4.: <br /> ... .. <br /> . o.o.�v,i,7.''�,Q.�VC�¢x �' ' <br /> . ..: . <br /> } .�...-�..'..a:Y;;.i:he'ti:Ai' �:. ': <br /> • <br /> ;. <br /> 'Q..Q�Q:.Q:'(�._ .�'VAtQ:t .' - . <br /> � -'LL.O'1��.0'b� Y'0'�O .a� .�..:. . �� �: <br /> Width �ft °o..e..:: �� a,�:. ...e .a;ti' <br /> <120mpi <10' Length�S'ft� <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;��sq. ft. x L ft. _ <br /> �u. ft. <br /> 2. Divide cu_ ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��cu. ft. = 27= ZZ�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;�'�cu. yd. x 1.4 ton/ <br /> F. ABSORPTION WIDTH <br /> l. Percolation rate in to 12 inches of soil is Z�O mpi AAsocption WidlhSizingTable <br /> Texture_�e��� �0�'�'0"R°�' Gallons RadoM <br /> M�mncs per I�h Soil Tcnwc ��a„�a� AMorMion WA�n <br /> . IA1%) squ�rc loa ro Rock l�ya <br /> WidN <br /> 2. Select allowable soil loading rate from table; Fu������ �rs`S'"' �'° �°° <br /> o.i�os ra�a��ms��u i.±o i.00 <br /> t.�r s,m <br /> ��/�fZ 0.1�0 5 Frc SaM 0.60 2.00 <br /> 6to15 Sandr(nam 079 I.5? <br /> 16�o)0 Loun 0.60 2.W <br /> )1�015 Si1�Loam 0.5f1 2.10 <br /> Sih <br /> 3. Calculate absorption width ratio by dividing rock layer '6io60 `�'''�'�" °•5 '." <br /> SiF <br /> SaMr CL <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; s�o�°���°,» �;;; o>0 6� <br /> 1.20 gpd/ft2 = O � gpd/ftz = Z •4� . <br /> 4. Multiply absorption width ratio by rock layer width to get <br /> required absorption width; <br /> Z.D x 1� ft = 70 ft <br />