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� University of Minnesota Pressure Distribution System Design -10/25/04 <br /> ns eoxed�d�pf�t must ae erMsrod,n�e reaf wrx ae caJan,�ed. <br /> Owsrte <br /> aew� <br /> 1. Seled number of perforated laterals: � T�� <br /> 2. Selecc:t perforation spacing= �3�ft <br /> (:�a4oRaf4(aFr.. <br /> 3. Since perforations should not be placed doser that 1 foot to <br /> fhe edge of the rodc layer(see diagram),subVad 2 feet from �-����� q i.f nti•k <br /> the rodc laye� <br /> 63 -2 ft= 61 ft '�;`�'�`.�;'"'"��•• <br /> 4. Determine the number of spaces belvveen perforations. <br /> Divide the length(3)by perforation spacing(2)and round down to nearest whole number. <br /> Perforation spaang= 81 ft/ 3 ft= 20 <br /> 5. Seled perforation size 1/4 inch <br /> 6. Number of peAorations is equal to one plus the number of pertoration spaces(4). <br /> "Check fiq�C 4 to essure dre number of perlaabons per Jatera/guaraM�ees <br /> <10%discheige velie6o►r. <br /> 20 spaoes+1= 21 perforetionsllateral <br /> �Maximwn Nwnbsr 1/4 inch pe�foratlons �i Max�num Number 3N61t�ch perforations <br /> IaEsral to rar�se<10X dls varfadon lebarel to uara�ee<1Mfi disCha va�latfo� <br /> Perforation <br /> Spacing Pipe Dismeter Spacin9 PiPe Dlerneter <br /> ft 1 inch 1.25 i�ch 1.5 inch 2.0 inch feet 1 inch 1.25 inch 1.5 inch 2.0 inch <br /> 2.5 8 14 18 28 2.5 12 19 25 39 <br /> =34 � aet ,�.'�+ h: "1� 26 �3 'k't:�� ��_ ,�� ;��. ;.37. . <br /> 3.3 � 7 12 �16 25 � � �3.3 10 � 17 , 23 , , 38 � <br /> . ....A;...' �` <br /> ,.� ; �', *.:: �:��r�'", : .16 2S '- � ,: r! 10,::<� {���,4 .�" <br /> :, �w �.r:... ... <br /> 5A 6 10 .�� d 14 22 5 9 15 20 31 <br /> 7. A.Total number of perforations=perforations per lateral(5)times number of laterals(1). <br /> 21 perfa/Iat x 3 Iaterals= 63 perforations <br /> B.Calailate the square foatage per perforation. <br /> Recommended value is 6-10 sqNpe�f.Do�not apply to at�ades. <br /> 1. Rodc bed area=rodc width(f�x rodc length(ft) <br /> 10 R x 63 ft= 630 ft� <br /> 2. Square per perforeU'�or�todc Bed Arealnumber o�perfs(6) <br /> 630.0 ft/ 63 perfs = 10.0 ft�/perf <br /> 8. Determine required flow rate by mulhptying the total number <br /> �P����(�)bY�P�Perforations see figure E-6) <br /> 63 perfs x 0.74 gpm/perfs= 46.6 gpm <br /> � n <br /> Head Pe rations diameter <br /> feet indres <br /> 3/16 7132 1/4 <br /> 1 0.42 0.56 0.74 <br /> �° .:, a�: o:eo ,.a <br /> 5 0.94 1.26 1.65 <br /> a. use�.o roa t«�nom�. <br /> b.Uae 2.0 teet for else . , <br /> `�� , <br /> 9. Detertnine Minimum Pipe Size _ , , . `••� <br /> A. ManNold on End. tt laterela are connected to header pipe ,,. ... . <br /> as shovm in Figure E-1,to select minimum required lateral �..E-�:M�.�.a a�d�.�, . <br /> diameter,enter figure E-4 or E-5 with perforation spaang and <br /> number of perforations per lateral.Select minimum diameter <br /> for perforated laterals= 2.0 inches <br /> B. Ceober Manifold. If perforated late�al system is attac�ed to �Fei,,,,M N;� i <br /> manifold pipe near the oeMer,like Figure E-2,perforated lateral length(3) _„. . ' ; <br /> aod number of parforations per lateral(5)will be approx'anately ' I <br /> one half of that in step A. Using these valu� seled - <br /> minimum diameter fo�peAorated lateral= 1.5 inches . `'Z�- •,. ' <br /> I hereby ' that I have completed this work in acxordanoe with all applicable ordinances,rules and laws. <br /> (signature) 810 (license#) 11/03/05 (date) <br />