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University of Minnesota Pressure Distribution System Design - 10/25/04 <br /> A9 boxed rodanQbs must be ente�ed,dhe resf w�l be cal�lated. <br /> O� <br /> s�wwe <br /> 1. Seled number of perforated laterals: 0 T"'�"""' <br /> rwoMewr <br /> 2. Select perforation spaang= �ft <br /> <:a-. tila�fahr�. <br /> 3. Sinoe perforafions should not be plaoad doser that 1 foot to _ "'"""" <br /> the edge of the rodc layer(see diagram).subtrad 2 feet from C�'--'�"1'�"" � <br /> �1C�OC�(�B�P@��@ fl ��•or....�k <br /> 63 -2ft= 61 ft ,�.�f.:�.,,,.,.�.;--��+- <br /> !\rl���.ry{I.R•_S• <br /> 4. Determine the number of spaces between perforations. <br /> Divide the length(3)by peAoration spaang(2)and round down to nearest whole number. <br /> Perforation spacing= 61 ft/ 3 ft= 20 <br /> 5. Selecc;t perforation size 1/4 inch <br /> 6. Number oT perforations is equai to w�e plus N�e number of peAoration spaces(4). <br /> •Chedc fpure C 4 lo assure Ihe number of perinrations per late�al guaren[�ees <br /> <10%disChe�e varialron. <br /> 20 spaoes+1 = 21 perforations/lateral <br /> � wn Numbsr of 1M nch -5 um Number of 3l16 inch pe <br /> Iaberal tp uararKee<10%diacha variatlon labral to ranbee<10M.dfsc variation <br /> P PerforaUon <br /> Spaang Pipe D�nellsr Spacing Pipe Diameter <br /> ft 1 inch 1.25 inch 1.5 inc� 2.0 inch feN 1 inch 1.25 inch 1.5 inch 2.0 inch <br /> y2,.��5, 8 �14g_� 18 28 2.5 12 1p9t 25 39 <br /> ."�l7W�Y.5 . � f33�`?,:` , s� , .��.� _?} i�.'�` �,'�'�.. ,'�¢ f Y.:;�," �'�. <br /> 3.3 7 12 16 25 3.3 10 17 23 µ n 36 <br /> �' ." < 7 ;#�.}�� `��<'�F.." ,.29 ;';s+t , tOj�'; i8 r�.� ' 93 . ,, <br /> 5A � 6 10 14 22 5 � 9 15 20 31 <br /> 7. A.T�al number of pe�forations=perforations per lateral(5)times number of laterals(1). <br /> 21 perfs/lat x 3 laterals= 63 perforatlons <br /> B.Calaila�e tF�e square footage per perforation. <br /> Recommended value is 6-10 ac�fllpeA.Does not apply to at-grades. <br /> 1. Rodc bed area=rodc width(ft)x rodc length(ft) <br /> 10 ft x 63 ft= 630 f'� <br /> 2. Square foot per perforation=Rodc Bed Area/number of perfs(6) <br /> 630.0 ft� / 63 perts = 10.0 ft�/perf <br /> 8. Detertniae required flow rate by mulGpiying tF�e tMal number <br /> �Perfo��$(�)bY�P�Perforations see figure E�) <br /> 63 perfs x 0.74 gpm/perfs= 46.6 gpm <br /> E-6 Perforation D M <br /> Head erforations diameter <br /> feet inches <br /> 3/16 7/32 1/4 <br /> 1 0.42 0.56 0.74 <br /> 2° 0.�' Q� 1.04 <br /> 5 0.94 1.26 1.65 <br /> a. use t.o rooc ror aingbdamy nomes. <br /> b.Use 2.0 feet for eke , <br /> ;:�j"' <br /> 9. Detertnine Minimum Pipe Sine - ' . . `••�,^ <br /> A. Manifoid on E�. If laterals are connected to hea�der Pipe ' , _.. .. <br /> . J , . ... .. ... <br /> as shown in Figure E-1�tO Se�RII�INTIUITI I�U�16�J Iate�al �W�E-1:MaYUk!looal�d al End o1 Nslwn <br /> diameter;enter figure E1t or E-5 with perforation spacing and <br /> number of peAorations per lateral.Select minimum diameter <br /> for perforated laterals= 2.0 inches <br /> _.____ __ <br /> B. Ce�Manifold. If perforated lateral system is attached to „�Fo��".,�:.�° - • . I <br /> manifold p�e near the ceMer,like Figure E-2,peAorated lateral length(3) _..; . <br /> and number of perforations per lateral(5)wiN be approximately _ <br /> one half of that in step A. Using these values,select , <br /> minimum diameter for perforated lateral= 1.5 inches • ^Z._ � <br /> I hereby certify that I have completed this work in accoMance with all applicable ordinances,rules and laws. <br /> � <br /> (sgnature) 810 (lioense#) 11/03/05 (date) <br />