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• o�� Job#�� <br /> asMr.ro� <br /> Tw,tw�swrT <br /> Pwos�ew►r� <br /> Univers' of Minnesota Mound Design Worksheet Site A <br /> �Gn�berthan 1%Siopes <br /> a F�ow <br /> F�timated 750 9Pd(see figure A-1) <br /> a��� x 1.5(safety factor)= 0 9Pd <br /> B. SEPTIC TANK LIQUID VOLUMES <br /> ��� �50 gallons(see frgure G1) <br /> Number of tanks/compartrr�ents � <br /> Effluent Filter (yes/no) Y� <br /> C-1 Septic Tank Capacily in GWona <br /> Number of Minimum C�aaty witli Capaaty wilh <br /> Bedroon�s Capaary Garb.Disp. Disp.�d Lift <br /> 2 or less ' �, . 1125 F�:>•E �� � . <br /> 3 or 4 , � "'f: : 1500 � � <br /> �. � � ,�,. � <br /> 5or6 . ' ,',�� �,� <br /> 7,8or9 „' � � � > >'' <br /> -+ '��s� <br /> C, SOILS(Site @V81Uation date) <br /> 1. D�th to restricting layer= 2.1 feet <br /> 2. Depth�pencolaGon tests= 12 inches <br /> 3. Texture � <br /> 4. Soil I�rate(see F'gure D-33) 0.60 9P�� <br /> p���e 6 MPI <br /> 5. %Land Slope 10.0 % <br /> D. ROCK LAYER DIMENSiONS <br /> 1. Mu�iply average design flow(A)by 0.83 to obtain requi�ed area ofi rodc�ayer:Item A x 0.83= <br /> 750 gpd x 0.83 fl�/gpd= � � <br /> 2, Detertnine rack layer width =0.63 ft"Igpd x Linear Loading Rate(LLR)(see LLR chart <br /> 0.83 ft�/gpd x 12.00 = 10.0 ft <br /> LLR Chart <br /> Pe�ic Rate I-LR <br /> <120 MPI <=12 <br /> >=120 MPI <=6 <br /> 3. Length of rodc layer=area divided by width= <br /> 630.0 ft/ 10.0 feet= 63.0 ft <br /> E. ROCK VOLUME <br /> 1. Multiply rodc area by rodc depth to get cubic feet of rodc <br /> 630.0 X 1.0 ft= 630.0 ft' <br /> 2. Divide ft3 by 27 ft3/yd3 to get cubic yards <br /> 630.0 ft3 / 27 = 23.3 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rodc in tons; <br /> 23.3 yd3 X 1.4 tontyd' = 32.7 tons <br /> Page 1 of 5 <br />