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' s� � Job#� <br /> Twswr�n�r <br /> PwooRwy <br /> Universi of Minnesota Mound Design Worksheet Site B <br /> Greater than 1%Siopes <br /> A. FLOW <br /> Estim�ed 75p gpd(see figu►e A-1) <br /> a measured x 1.5(safety factor)= 0 9Pd <br /> B. SEP'TIC TANK UQUID VOLUMES <br /> ���ty 2�0 g��ons(see figure G1) <br /> Number of t�ks/�hr�ents 0 <br /> Effluent Filter (yes/no) Y� <br /> G1 Srpfic Tmk Cap�c�ty in GWo� <br /> Number of Minirrwm Capacity witl� Capacity with <br /> Bedroortis Capacity Garb.Disp. Disp.and lift <br /> or less s:,.•* �� 1125 ;t,.# <br /> � F�$:- � ' <br /> 3 or 4 ,�r 1500 ": � - <br /> 5 or 6 � t�^ 2250 z:�� ' <br /> 7,8 or 9 .;s�,�`� , � ���'`�: 3000 `i�° � <br /> C. SOILS(Site eve/uation d�a) <br /> 1. Deqh to reshic6ng laye.�= 1.8 feet <br /> 2. Depth of peroola6on tests= 12 inc�es <br /> 3. Te�cdne bam <br /> 4. Soil loa�ng rate(sse Figu�e D-33) 0.60 �dl fl <br /> Penodabon rate 6 MPI <br /> 5. 96 Land Sbpe 6.0 96 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. N�iHply average design flaw(A)by 0.83 to ot�ain required area of rock layer:Item A x 0.83= <br /> 750 gpd x 0.83 ft�/gpd= 630 it� <br /> 2. Detertnine nodc layer width =0.83 il`/gpd x Linear Loading Rate(LLR)(see LLR chart <br /> 0.83 ft/gpd x 12:� = 10.0 ft <br /> LLR Chart <br /> P�k R�e LLR <br /> <120 MPI <=12 <br /> >=120 MPI <� <br /> 3. Length of rock layer=area divided by width= <br /> 630.0 it� / 10.0 feet= 63.0 ft <br /> E. ROCK VOLUME <br /> 1. MulGply rodc area by rock depth to get cubic fcet of rodc <br /> 630.0 X 1.0 ft= 630.0 ft3 <br /> 2. Divide ft3 by 27 ft3/yd3 to get cubic yards <br /> 630.0 ft3 / 27 = 23.3 yd3 <br /> 3. Multiply cubic yabs by 1.4 to get weight d rock in tons; <br /> 23.3 yd3 X 1.4 ton/yd3 = 32.7 tons <br /> Page 1 of 5 <br />