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University of Minnesota Pressure Distribution System Design - 10/25/04 <br /> aaea,rad re�s�,r ae�a,nb,�ar�a.�area. <br /> o� <br /> 1. Selec�number of perforated laterals: 0 T�� <br /> 2. Selec;t perforation spacing= 03 R <br /> �.«.:k�.�.�, <br /> 3. Since perforations should not be placed closer that 1 foot to :......-'..__..._.;.....-f. t2- <br /> }�18 O��8�C� fa.���....s.a�t�..u.........�n_--r <br /> edge ay�er(see diagram)�subtred 2 feC1 frorrl -y��..,.•k <br /> Uie rodc lay�er <br /> �-2ft= 61 ft ���tiv.,,,.,.�d--�,�• <br /> t'\/�v��nK�.t'-!�' <br /> 4. Detertnlne fhe number of spaces between perforations. <br /> Divide the tength(3)by perforeaon spacing(2)and round drnm to nearest whole number. <br /> Perforation spaang= 61 ft/ 3 ft= 20 <br /> 5. Seled perforation size 1/4 inch <br /> 6. Number of peAorations�equal to one plus the nunber of perfwation spaoes(4). <br /> 'Chsck fqwe E�to assure Ghe number of pe�ations per/atera/guaraMees <br /> <f0l6�CNarge ve�ie(ion. <br /> Zp spaoeg+1= 21 peAorations/lateral <br /> � wn Nwnber 1/4 -6 um wnber 3/16 inch perforaHons <br /> la�sral to ranEae<10X varlatlon laberal to uara�Eee<70'�f.dlscha variation <br /> Pe�foration <br /> Spac,GtB P�e DiameAer Spedng Pipe Dfameter <br /> , R 1 inch 125 inch 1.5 incF► 2.0 irx:h feet 1 inch 1.25 inch 1.5 inch 2.0 inch <br /> 2.5 8 �14q 1 8 2.5 ♦12 19 �2u5 39 <br /> ?�a r�,r;:� •�r:�'r ;��'i ,i :�� ik:S.�S�,j"'-�,'s nml� , _ '`7$ . '.;a�,. '��.� .. <br /> 3.3� � 7 12 16 ~ �•. 25 3.3 10 17 23 � . 36 <br /> s.".�n` _ '7;• �t;. ,F�� _;�3 `.;rr3;. , :#�.:�,. �$ ;��. ��{ <br /> 5.0 ' 6 10 n . 14 22 5 9 15 2p 31 <br /> 7. A.Ta�l�umber of perforations=pe�forations per laferal(5)times number of laterais(1). <br /> 21 perfs/lat x 3 laterals= 63 perforatlons <br /> B.Caku�e tt�e square footage per perforation. <br /> R�eoarxnended va�ue is s-�o sqn/perf.ooes not appy to ac-grades. <br /> 1. Rodc bed area=todc w(dth(ft)x rodc length(it) <br /> 10 ft x 63 ft= 630 it� <br /> 2. uare toat per perforation=Rock Bed Area/number of perFs(6) <br /> 630.0 fl/ 63 perfs = 10.0 ft�/perf <br /> 8. Determine required flow rate by multiplyin�the total number <br /> of perforations(6A)by floMr per perforations(_see figure E-6) <br /> 63 perfs x 0.74 gpm/perfs= 46.6 9Pm <br /> �Pe�foradon Discha e in <br /> Pe rations d meter <br /> feet incfres <br /> 3/16 7/32 1/4 <br /> 1 0.42 0.56 0.74 <br /> r a� o� ,.oa <br /> 5 0.94 1.26 1.65 <br /> a. tlse�.o roa ror akgle-tamNy nort�. <br /> b.U�Se 2.0 feel for else � <br /> ti�..,. <br /> 9. Detertnine Minimum Pipe Siae � . . -••��, <br /> A. Manffold oo End. If laterais are oonnected to header pipe __ . <br /> .. ... <br /> as ahovm in Figure E-1,to select minimum requir+ed laterai '�..E-�:M�.��d E�a w.� <br /> diameter,enter figure E�4 or E-5 with perforation spacin�and <br /> number of perforations per lateral.Seled minimum diameter <br /> for perforated laterals= 2.0 inches <br /> -------__ __ _ _-- - - -: <br /> B. Cenbsr Manifold. If pe�forated lateral sysbem is attached to ^�F� w;� ._ <br /> manifold p�e near the oeMer,like Fgure E-2.perforated lateral length(3) ~ .,. ._ <br /> a�d number of peAoratio�a per lateral(5)vrill be appro�arnatey ' <br /> one half of that in atep A. Using theae valuea seled - , <br /> minimum diameter for perforated lateral= 1.5 inches . 'Z��._ ,',' ' <br /> I hereby ' that I have completed this work in accordance with all applicable ordinances,rules and laws. <br /> (signature) 810 (lioense#) 11/03/05 (date) <br />