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septic design-2005
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Last modified
8/22/2023 4:41:55 PM
Creation date
4/11/2017 2:27:01 PM
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x Address Old
House Number
125
Street Name
Kintyre
Street Type
Lane
Address
125 Kintyre Lane
Document Type
Septic
PIN
3211823430017
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• s�sww�aa Job#� <br /> T�aa►r��T <br /> Pwoo�ewy <br /> Universi of Minnesota Mound Design Worksheet S�e A <br /> Gr�eate�than 196 Slopes <br /> a �.ow <br /> Esdmated 750 9pd(see figure A-1) <br /> or measured x 1.5(safety factor)= 0 9Pd <br /> B. SEPTIC TANK LIQUID VOLUMES <br /> SepUc tank ppacity 225p g�lons(see figwe G1) <br /> Number d tanks/canpartments 0 <br /> Eflluent F�er (Yesha) Yes <br /> C-18�plic Tank CapacNy In G�bns <br /> Number of Minirtwm Capaciry with Capacity with <br /> 8edioon�s Capaaty Garb.Disp. Disp.and lift <br /> � tu: : '�x�., ,. � r ". <br /> 3 or 4 ���';� �, ' ��� �" 1500 ` <br /> �`. <br /> 5 or 6 �� �� .� 725p � : <br /> � <br /> ��#y� "3 r <br /> 7�8�(.9 ,.I...,�e�i. �' .� r. <br /> C. $�.$($�B BV8�U8ff0/1 d8t8) <br /> 1. Deph to reshiding layer= 1.6 feet <br /> 2. Depth d pe�daUon tests= 12 inches <br /> 3. Te�dune loam <br /> 4. Soil loa�ng rake(see Figure D-33) 0.60 9pd�� <br /> Perodaafi�on rate 7 MPI <br /> 5. 96 Land Slope 8.0 96 <br /> D. ROCK LAYER DII�NSIONS <br /> 1. Multiply aver�e design flow(A)by 0.83 to obtain required area�rodc layer:Item A x 0.83= <br /> 750 �d x 0.83 ftlgpd= 630 ft <br /> 2. D�e.mrine rodc layer width =0.83 ft`/gpd x Linear Loading Rate(LLR)(see LLR chart <br /> 0.83 ft�lgpd x 12.00 = 10.0 ft <br /> LLR Chart <br /> Perk Ra�e LLR <br /> <120 MPI <=12 <br /> >=120 MPI <� <br /> 3. Lengtf►of rodc layer=area divided by width= <br /> 630.0 ft� I 10.0 feet= 63.0 ft <br /> E. ROCK VOLUME <br /> 1. MulUply rock area by rock depth to get cubic feet of rodc <br /> 630.0 X 1.0 ft= 630.0 ft3 <br /> 2. Divide fC�by 27 ft3/yd3 to get cubic yards <br /> 630.0 ft3 / 27 = 23.3 yd' <br /> 3. Multiply cubic yards by 1.4 to get weight of rodc in tons; <br /> 23.3 yd3 X 1.4 tonlyd3 = 327 tons <br /> Page 1 of 5 <br />
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