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3720 Jacobs Mill Road - 32-118-23-24-0008
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Last modified
8/22/2023 4:40:06 PM
Creation date
3/15/2017 11:46:14 AM
Metadata
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Template:
x Address Old
House Number
3720
Street Name
Jacobs Mill
Street Type
Road
Address
3720 Jacobs Mill Road
Document Type
Septic
PIN
3211823240008
Supplemental fields
ProcessedPID
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'��'7��' �i � MOUND DESIGN WORKSHEET 5 <br /> ��,�;,,, r�-/� (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day <br /> �_ ( d) <br /> Estimated S G� �7C� Numbu ?ypel Type➢ TypeID Type <br /> or measured x 1.5 = gpd. �f �v <br /> 2 30o ns i so � <br /> B. SEPTIC TANK LIQUID VOLUMES a � 330° zsb °f"� <br /> .- s �so aso z�a "�"� <br /> ��-s � gallons 6 90o su s3z Type l. <br /> 7 1050 60� 370 ll m <br /> 8 1200 675 408 � <br /> C. SOILS (refer to site evaluation) � � j� `��� <br /> � � Sc lic Tank Ca aotirs(in allunsl <br /> 1. Depth to restricting layer = O� inches ''�_feet �4�a�=��,y <br /> Numhcr�if Minirtwm[Jyuid Liyuid capadry w�N wiU dis(wsal& <br /> 2. Depth of percolation tests - /Z inch s e�n•» ����y g�aged�spusal �,h;�;� <br /> 2iK kss 750 1125 1500 <br /> 3. Texture �v��� Percolation rate /S � mpi ���.< <� �5� 2� <br /> s����s �soo zzso 3aoo <br /> 4. Land slope �S % 7.R ur Y z� 3� � <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> �-�O gpd x 0.83 sq. ft./gpd = �sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ /�G ft. <br /> 3. Len of rock layer = area =width = � n=.a n e� a a�o °�.�a °e� � aa ° <br /> � o:Ao ooaQo oan.b Q na <br /> �� � sq. ft. - �ft. _ �� ft. ��° nD�P poC�4 :a. <br /> �Q p�p�o Q a a e.a'o o�o o .� <br /> 400 0�Q�o p0 PD'�?Da��D�� 9b��� <br /> Wl/7}}� /// �f a0000a o'�D'QOpOD D o0 oD� <br /> uLLl � � <br /> <120mpi <10' Length�ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; sq. ft. x <br /> ft. _(��cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu. ft. -27 = �3 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; z� cu. yd. x 1.4 <br /> ton/cu. yd. =.�2 tons. <br /> F. ABSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is��L mpi �a���� Gallons RarioofAbsorpuoo <br /> / Minutes pa Inch Soil Tezture per day per widt6 to Rock <br /> Texture �+�'g r� (MPI) squazc fooc laycr Vlridth <br /> Faster Nan 0.I Coarse Sand 110 1.00 <br /> 0.1 to 5 Sand 1.20 1.00 <br /> 2. Select allowable soil loadinp rate from table; o.��o s Fine Sand o.6o Z.00 <br /> O 6 to 15 Sandy Loam 0.79 1.52 <br /> (J p� 16 to 30 Loam 0.60 2.00 <br /> � �I'�/� 31 to 45 Silt Loam 0.50 2.40 <br /> 46 to 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer s�o�w���o c�ay o.zo 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ftz= i /' gpd/ft2 = �,��' <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �_x /U ft - Z� ft <br />
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