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2 septic designs-not sure which one goes with permit
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3675 Jacobs Mill Road - 32-118-23-24-0012
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2 septic designs-not sure which one goes with permit
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Last modified
8/22/2023 4:40:15 PM
Creation date
3/15/2017 11:03:33 AM
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x Address Old
House Number
3675
Street Name
Jacobs Mill
Street Type
Road
Address
3675 Jacobs Mill Road
Document Type
Septic
PIN
3211823240012
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• ' MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. �,�W Estimated Sewage Flows in Gallons per day <br /> Estimated ,�O �C� Numbc 7'ype I Type Q) Type ID Typr <br /> or measured x 1.5 = gpd. {� �v <br /> z 30o zzs iso � <br /> B. SEPTIC TANK LIQUID VOLUMES 4 � 3� Z;� °f� <br /> s �so aso 2sa °'�"� <br /> 2ZS0 gallons 6 90o sas 332 T,'a,. <br /> � ioso 60o s�o u� <br /> 8 1200 675 408 �7 <br /> C. SOILS (refer to site evaluation) �d� <br /> ' lieTank wlies(in allw�sl <br /> 1. Depth to restricting layer = 2 inches 2' feet �qwd�����Y <br /> Numl+er af Minimum tiyuid liiryid opacry wiN with d�sposal& <br /> 2. Depth of percolation tests = f Z inches �°^� ���Y �°°��"' �"`�'°` <br /> 2�x kss 750 1125 I500 <br /> 3. Texture �dr�rY✓ Percolation rate / -Z Z mpi �.x< �� �� Z� <br /> s����s �sao nso 3000 <br /> 4. Land slope o _ � °�O 7.A�n Y �� � � <br /> O - 3 A�TS•'� <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> �gpd x 0.83 sq. ft./gpd =�ZZ sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ /O ft. <br /> 3. Len�of rock layer= area=width= ,;,�p,,, o,,,, e D 8)a.e.e.e ea -. e oe.e, b Q, o <br /> w Aaa n r g <br /> ��sq. ft. — �ft. _�2. ft. �:t�ao1�S�be���; o <br /> a.QOpbp°'QA:Re 6?..aooe4 <br /> . o.�r.�ae� ea6QD.��Dp.,Lb. ' .:. � . .: . -. . <br /> Qfl: . <br /> W��}� ��t Q00000 edC00�OD D oe+ o oD e <br /> LLl 1• <br /> <120mpi <10' Length�ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�sq. ft. x� <br /> ft. _�Zcu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu. ft. =27 = 2�cu.yd. <br /> 3. Multi pl y cubic yards b y 1.4 to get wei ght of rock in tons;�cu. yd. x 1.4 <br /> ton/cu. yd. _�tons. <br /> F. ABSORPTTON WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is�Z mpi ����� c�►,� �o�r��� <br /> � O� � Minut�a pc inch Soil Textuce pa day per width ta Rock <br /> Texture � cM�� �r�� ��R wd� <br /> � F���cn�,o.� co�s�a �.io �.00 <br /> o.��s sar,a �.zo i.00 <br /> 2. Select allowable soil loadin rate from table; o.��a s Fnc Sand o.6o z.00 <br /> g b�o�s s�ay�� <br /> i d gpd/ft2 31ro45 sa�°�, 0.6o z:oo <br /> 46 ro 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer s�o�w��zo c�aY o�o s.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loadin rate; <br /> 1.20 gpd/ftz= � � gpd/ftz= �•(J'� • <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �_x��ft=��ft <br />
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