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. . ' 1, <br /> � r <br /> � ' � MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. �O`/�J Fstimated Sewage Flows in Gallons per day <br /> Estimated ,�v �7C� Nu�ber Type 1 Type Q) Type ID Typr <br /> or measured x 1.5 = gpd. �v <br /> z soo zu iso �, <br /> B. SEPTIC TANK LIQUID VOLUMES 4 0 330s Zzs� °`'� <br /> ZZSO gallons 6 � su 3�i r,',�,. <br /> � ioso �oo s�o n a <br /> 8 1200 675 408 � <br /> C. SOILS (refer to site evaluation) `�� <br /> - �� .��� � <br /> 1. Depth to restricting layer = 2 inches 2' feet �q�.��Y <br /> NioMer af Minimum L�yuid liyuid wpaoty wiN with d1s�wsai& <br /> 2. Depth of percolation tests= � Z inches B�^� �e��Y �°��' ''��°� <br /> x«� �so �iss �soo <br /> 3. Texture r+�/ Percolation rate -t Z mpi :�,H< �� �� � <br /> s�x F i sao suo 3aoo <br /> 4. Land slope v - '� % 7.R m 9 Z� 3� � <br /> O - 3 A�Ts,�� <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> ��b gpd x 0.83 sq. ft./gpd =��sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ /4 ft. <br /> 3. Len�of rock layer = area=width = , A. , ,, a��A�A e.e�•=o�o °:b:ao a e m:b. a ° <br /> - � _�L ���qg�'�D o�a � • � <br /> �/1 Z Sq. ll. � ll. ll. ak0'"°A uS&ae:e-�.e°�.aa«e p. . .. . ... ...: ; . <br /> 0 <br /> 4v:�:a•e a a aon b�n b p%:. <br /> WI�LLl��l �.4p�.,p . �..:o.Op.p�..pOD..II . a::..:o oD.e. <br /> <120mpi <10' Length�ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; ZZ sq. ft. x� <br /> ft. _�2cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu. ft. -27=�cu.yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;�,cu. yd. x 1.4 <br /> ton/cu. yd. _�tons. <br /> F. ABSORPTION WIDTH Absorption WidW Siziag Table <br /> 1. Percolation rate in top 12 inches of soil is�mpi ��w�;� c�u� �o�rA�� <br /> Mioutes pa Ix6 Soil Texture per day per width to Rocic <br /> Texture L o q•,n cM�� ���« �Yawd� <br /> Famer ehan 0.1 Couu Sand 1.20 1.00 <br /> O.I w 5 Saod 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; 6�o�5 sF�ys� o.�o z.00 <br /> ���d p�d/ft� �6�30 ►.o�, 0_6o z:oo <br /> -+�- a!' 31 ro 45 Silt Loam <br /> 46 to 6p Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer s,o,V«a,��Zo c�Y o.zo 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loadin rate; <br /> 1.20 gpd/ftz= � � gpd/ftz= �.U� - <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �_x1Q_ft =�ft <br />