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� <br /> i T <br /> � MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. �OW Fstimued Sewage Flows in Galloru per day <br /> d) <br /> Estimated�gpd N o� Tra� T�n r�m T� <br /> or measured x 1.5 = gpd. - <br /> 2 �oo vs �so � <br /> B. SEPTIC TANK LIQUID VOLUMES 4 � � Z� °f�" <br /> s �so aso ZQa "''"� <br /> ��r�--{� gallons 6 90o sas ssz r,�►. <br /> � ioso 600 3�o a« <br /> 8 1200 675 408 IIi <br /> C. SOILS(refer to site evaluation) ,� , ,� . �,� .�,;� , �� <br /> 1. Depth to restricting layer=�Z inches�feet ��a���y <br /> Nimi+er of Minimum liyuid l�yuid�dty wpA wiN disposal& <br /> 2. Depth of percolation tests = �inches �°^� ��' �m�'' �ft`�'°` <br /> s,x� iw uu isao <br /> 3. Texture L��irv Percolation rate 2 2 mpi j.K• �� �� � <br /> 4. Land slope .�,% 75A�irr9 �� � � <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> �gpd x 0.83 sq. ft./gpd =.5�sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = J f� ft. <br /> 3. Length of rock layer =area=width= Q�PAke� ,,a:� R a-�:.:a.,aa . .-° , �-.:, a, o, <br /> v'�;-rr� sq. ft.= !1� ft. _ �U ft. a_..�a�.d�¢.��{�o � . <br /> .{j�0���0'.°�QA.O�Ga�'Vd9d D'P <br /> 9.�:. <br /> W1�Lll�ll Qoe�o'•s" .e�0'0'�oa 'ff 'yn' e :oD•. <br /> <120mpi <10' Length_�ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;-a�z�sq. ft. x I <br /> ft. -�'�cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards, <br /> �cu. ft. =27=�cu.yd. �. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons��-�cu. yd. x 1.4 <br /> ton/cu. yd. _�tons. <br /> F. ABSORPTION WIDTH ���oo w�a�n s�g Tan�e <br />� 1. Percolation rate in top 12 inches of soil is ?Zmpi �a��x�� c�,�� x�o�rnn�� <br /> Texture �o-� ����� Sal Tacmce ��y p« widt�to Rock <br /> y'�✓ (A4PI) e9uats foot Layer VVidth <br /> Fuoer thaa 0.1 Couse Sand 1.20 1.00 <br /> O.I to 5 Sand 1.20 1.00 <br /> 2. Select allowable soil loadinp rate from table; o.��s Fine Sand o.�o �.00 <br />� O 6 to 15 Saody Loam OJ9 1.52 <br /> � �� ar�/� 31 to 45 Sik oam 0.0 2.40 <br /> 46 co 60 qay Loam 0.45 2.67 <br /> 60to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer �'°`�`""°12o c,�Y o.zo s.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2= � O gpd/ftz= ?. D <br />' 4. Multiply adsorption width ratio by rock layer width to get <br />� required adsorption width; <br /> Qx_�ft=�ft <br />� <br />