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� � � •r • <br /> F-17 <br /> Pirn�rP SEL•ECTTON PROCEDURE <br /> EIO PERfORAT10N OF A PERFOFtATED LATERAL <br /> A. Determine pump capadty: , �-� . <br /> Gravity Distribntion r».w <br /> 1. Minimum suggested is 600 gallons per hour(10 gpm)to stay ahead of c�;i?•.`:.'^' '` �r N��y��k(r far• <br /> W8�!llSe l3�. ta�►SN 1Mr �'Ysh N�M b.r a.w cwww <br /> '��IM ,rY�M��) <br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 , ^�*^��^°"'�°"°��°^+°'� <br /> ���w. �. <br /> gallons per hour(45 gp�to prevent build-up of pressure in drop box. ,� '-��.�.� �r�.E.w <br /> .��«.�.►.� <br /> ;...:•��.:• . . ....:.., /YM/lw LIa1N ol <br /> Pressure Distibution �. c,..,,,.,,,,,�, ..�+••«�.�.,.� <br /> 3.a. Select number of perforated laterals 3 w+�v,. � � � <br /> b. Select perforation spacing=__.�.__feet .°�.�.s�w�..�"' <br /> c. Subtract 2 ft from the rock layer length. <br /> -.��-2 ft=�feet <br /> d. Dete�rmine the number of spaces between perforarions. <br /> Length �etf.spaCing=�ft.+�_f t.=1,�spaces Requjred Perforaeon A.uh e <br /> e. �spaces+1=J.2_Perforations/lateral �8��P����SP�+� <br /> f. Multiply perforations per lateral by number of laterals to '�e ,,,P„� ��� <br /> get toWl number of perforadons.;�; x�Q,,_�.1_perforations. �� �2 �` <br /> g. .� X��-�,_�sp� �,� y L►�,�Us c,��.�� =sog-►�J r►.,�. 1.Oa 0.56 0.74 <br /> SELECI'ED PUMP CAPACITY�"�$pm 2.Ob 0.80 1.04 <br /> B.Determine head riquirements: a.Use for single family homes <br /> 1. Elevation difference between pump and point of discharge. b.Use for all other applications <br /> � _feet <br /> 2. If pumping to a pressure distribution system,five feet for pressure <br /> required at manifold if gravity system,zero. <br /> �_feet <br /> 3. Fricdon loss <br /> a. Enter Eriction loss table with gpm and pipe diameter. �P�L�B� <br /> Read friction loss in feet per 100 feet from table. Poinc oc Discharge <br /> F.L._ �.� ft,/100 ft oE pipe Tq�.� <br /> b. Determine total pipe length from pump to discharge Elevaaan Differencel <br /> point Add 25 percent to pipe length for fitting p�p y3 � <br /> loss,or use a fitting loss chart. Equivalent pipe <br /> length-1.25 times pipe length= F-18b <br /> �x1.2S=�_feet <br /> c. Calculate total friCtion loss b multi 1 n 1.5 inch 2.0 inch 3.0 inch <br /> Y P Y� 8 gpn, c�;o��«.�iao a er P�a <br /> friction loss in ft/100 R by equivalent pipe length. l0 0.69 0.20 <br /> Total friction loss= a,� x f_z +100=�_feet 12 0.96 0.28 <br /> 4. Total h�d required is the sum of elevation difference, �4 1.28 0.38 <br /> special head requirements,and total friction loss. 16 1.63 0.48 <br /> 18 2.03 0.60 <br /> 20 247 0.73 0.11 <br /> �_+ g +�_ 25 3.73 1.11 0.16 <br /> (1) (2) (3c) 30 5.23 1S5 0.23 <br /> 35 7.90 2.06 0.30 <br /> 40 11.07 2:64 0.39 <br /> TOTAL HEAD _!�feet � 45 14.73 3.28 0.48 <br /> 50 3.99 0.58 <br /> 55 4.76 0.70 <br /> C. Pump selection bo s.bo o.s2 <br /> � 1. A pump must be selected to deliver at least <br /> �_gpm (Step A)with at least �feeE of total head(Step B). <br />