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• � ° MOUND DESIGN WORKSHEET <br /> � (For Flows up to 1200 gpd) <br />• A. F'j,�w Estirnated Seva6e Flow in Gallons pa Day(gpd) <br /> I <br /> Estimated � � gpd N�+� <br /> ot 'iype t 7ype!I 'iype Ill 7ype rv <br /> or measured - x 1.5 = - gpd. s�� ! <br /> z 300 2?S 180 60. <br /> .r <br /> B. SEP'ITC TE1NK LIQUfD VOLUMES } ' s � i'so � '� j <br /> �-� 0 a� l-/OOt7 g�0I1S � 6 900 525 732 '"° ' <br /> 7 1Q50 600 370 �� <br /> 8 1200 675 408 <br /> C. SOIIS (refer to site evaluation) ,� �� N,�� � �� <br /> 1. Depth to restricting layer= a y � a� inches a °� � �, ; <br /> 2. Depth of percolation tests = 1 � inches `'"'° `'"' I <br /> 3. Percolation nte 4, O mpi 2i a`� i'.oSOoo i'.'so <br /> 4. Land slope � % ;a s � ,,� <br /> wa 9 See!iy C-6 (x 1S) <br /> D. ROCK LA,YER DIlv�1SIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock � <br /> layer:A x 0.83 = , � <br /> 7�0 . gpd x 0.83 sq. ft./gpd =��sq. ft+►�o= (.�S ya <br /> 2 Select width of rock layer (10 feet or less) = l� ft. <br /> 3. Length of rock layer= area i width= R�g� <br /> �_sq. ft.+ ��ft. _�_ft. ,.,.,.,.,.,.,...,.,.�.,...,.,.,., <br /> 1•1•1•1•I•I.r•�•t�•I�t•1•t•t•I• <br /> �•1•1.1N•1•1•�•'M1��•1�tiA�1�1•♦ <br /> �r•r.�.f•r•r.r•�•i r•�•r•r•r•r•�• tdth S10 ft. <br /> •ti.�.�.�.ti.ti.ti.ti.L•ti.ti.�.ti.�.�•ti <br /> r•f.�•i•r•r•r.r•��•r•�•r.r.r•r• i <br /> 1•�•1NN.tiMM•�•�•�•�•1•�•1H•1 � <br /> •���.f.f.f.f�r��.r�����.��f�f.f. <br /> E. ROCK VOLUME ~- �'�'�' -' � <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; • � <br /> L5s4 sq. ft. x ,�os ft. =21�cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft:/cu. yd. to get cubic yards; <br /> 2�cu.ft. y 27=�_cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu.yd.x 1.4 ton/cu. yd. _�4! tons. <br /> � <br /> F. AD���N�D� G 1��'� L 0�Y✓1 Width Sirin Lbk <br /> 1. Percolation rate in top 12 inches of soil is �,o mpi ��,�,,,��,�,k �� Aa d <br /> M�„�,k, „�, SoilTexture ,:,� ";,"' <br /> c�,w �.. .:..�., <br /> N <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand 1.20 l.00 <br /> �`- � $Pd/ft� o.i ro s Sand w 1.zo 1.00 � <br /> 0.1 to 5 Fne Sand �•� Z•� <br /> 6 to 15 ndy Loam �•�9 1�Z <br /> 3. Calculate adso hon width ratio b dividin rock la er t6 co ao t,oam o.bo 2.00 <br /> rP � Y 8 Y 31 to 45 sac t,�m oso 2.ao <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �co bo cia t,o�, o.as 2.6� <br /> 1.20 gPd/ftZ+ .�S gpd/ft�_ � .le� Slower�han 120 Clay 024 5.00 <br /> "$oil hivin6� x or ma!d Cux or reeY Cux sand <br /> 4. Multiply adsorption width rario by rock layer width to get <br /> required adsorption width; <br /> �'L� x_�ft=�L•� ft <br /> i <br />