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1997-009562 - new septic system
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465 Hunter Pass - 25-118-23-31-0007
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1997-009562 - new septic system
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Last modified
8/22/2023 4:14:12 PM
Creation date
3/2/2017 12:26:01 PM
Metadata
Fields
Template:
x Address Old
House Number
465
Street Name
Hunter
Street Type
Pass
Address
465 Hunter Pass
Document Type
Septic
PIN
2511823310007
Supplemental fields
ProcessedPID
Updated
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• MOUND DESIGN WORKSHEEI' <br /> (For Flows up to 1200 gpd) <br /> , <br /> A. �.OW Estimned Sew�6e Flo�in Galloe:pa Day(g� <br /> Estimated��_gpd <br /> or measured x 1.5 = -- gpd. B�,f„ �`� �`" '�'�`�" 7Yx rv <br /> z soo i2s �so �. <br /> 3 �50 300 218 •� <br /> B. SII'TIC TANK L.IQLJID VOLtJMES � � �ao 3�s zs� ,� <br /> S 7S0 450 294 � <br /> 6 900 525 332 '"� <br /> �-1�..Sl� � )-)Oo o g OI1S 7 1Q50 600 370 e0i <br /> 8 1200 675 �OB �� <br /> C. SOILS (refer to site evaluation) � ,.� <br /> �� �i N�bc �� ��� <br /> 1. Depth to restricting layer= �� -to aa, inches B� G,,,,,, p;,,.,, <br /> 2. Depth of percolation tests = 1 �." inches `'"" ''""' <br /> 3. Percolation nte ���� mpi 2j a 4� �'.oSOoo i'.'s o <br /> 4. Land slope 4 . % ;a a � �° <br /> wa 9 Ses 6y C-6 (x 1S) <br /> D. ROCK LAYER DIIv�1SIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = <br /> , <br /> �S� • gpd x 0.83 sq.ft./gpd =,��,sq. ft.-�►�����s�+'' <br /> 2 Select width of rock layer(10 feet or less) _ �o ft. <br /> 3. Length of rock layer=area+width= R�g� <br /> �sq. ft.+ 10 ft. _��,ft. ..,.,, ..,.,.........,.,w....., <br /> r•r.i.S.r.�.�.�•r.�•r•r�•r.r.r• <br /> ti•�.�.�•�•�.ti•ti•�•�.�•ti•ti•ti•� ti•� <br /> ��;�tif;��rti�•�•r•f�•�•r•r•r•r•r• �dth 510 ft. <br /> ti•�•ti.ti.�•ti.ti•�•�•�•ti <br /> r•r•r•�•r•r•�•r.r�•r.�.r.f.r•�• <br /> +•�.�•�•�•ti•�•�•ti•ti•�•�.�•�•�•�•ti <br /> .r.�.f.�.f.f.r.i•r•r.r.�.f.f.r.f. <br /> E. ROCK VOLUME �- �'�'g`� --' <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; <br /> �sq.ft.x►,_�ft. _�cu. ft. <br /> 2. Divide cu.ft.by 27 cu.ft:/cu. yd. to get cubic yards; <br /> �cu.ft. i 27=�cu. yd. <br /> 3. Muldply cutiic yards by 1.4 to get weight of rock in tons; <br /> �cu.yd.x 1.4 ton/cu.yd. _�, tons. <br /> F. A�OR��N�D� LL A l.01�w� WSdth Si� 'Lbk <br /> 1. Percolation rate in top 12 inches of soil is I��� mpi r�,�,,,,�,�,4 �� �.�d <br /> Ms„u��t�c►, Soil Textur+e �.� �,'ad <br /> �� .:.e.�a <br /> M <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand i.2o i.00 <br /> � gpd/ft2 o.i ro5 Sana t.2o �.00 <br /> 0.1 to 5 Fne Sand" 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1�2 <br /> 3. Calculate adsorption width ratio by dividing rock layer ai io as ssi a m oso 2.a�o <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to bo cia �.o�, o.as 2.6� <br /> 1.20�d/{t�y .ti� �d/ft2= �.L 7 Slower�than 120 CIaY 024 5.00 <br /> "Soil havina 507C or mae d fine or vey Cu+e aand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a•�7 x �o ft=a�.7 ft <br />
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