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1997-009559 - new septic system
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425 Hunter Pass - 25-118-23-31-0008
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1997-009559 - new septic system
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Entry Properties
Last modified
8/22/2023 4:14:16 PM
Creation date
3/2/2017 12:08:14 PM
Metadata
Fields
Template:
x Address Old
House Number
425
Street Name
Hunter
Street Type
Pass
Address
425 Hunter Pass
Document Type
Septic
PIN
2511823310008
Supplemental fields
ProcessedPID
Updated
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, MOUND DESIGN WORKSHEET <br /> (For Flows up to I200 gpd) <br /> , � <br /> A. FLOW � Estir++ned Seaa6e F1o.v in Gallons pa Day(gp� <br /> Estimated 7 tn �C� N o(� 'fype I 'Iype II 'Iype!12 'Iype IV <br /> or measured - x 1.5= - gpd• �� <br /> s aoo iis �so � <br /> 3 450 300 218 •� <br /> B. SEPTIC TANK LIQUID VOLLTMES � + 6°° 3�s z�s� •� <br /> s �so .so sv� : <br /> 6 90o su 332 � <br /> ►_ ��Sn � i-�ovo g ons �� <br /> 7 1Q50 600 370 <br /> 8 1200 675 408 <br /> C. SOIIS (refer to site evaluation) N„�� <br /> '�..r.. �.r. <br /> 1. Depth fio restricting layer= i�s�_;.�y,�* a�inches "����;a� B °� �,,,�, ;;�,, <br /> 2. Depth of percolation tests = � a.'' inches `'"'' `'�``' <br /> 3. Percolation rate �2.� mpi 2s,�'� ;� ;�,'�'� <br /> 4. Land slope 3 % s«b i.soo z.�so <br /> �a a zaoo s.000 <br /> wer 9 See fiy C-6 (x 1 S) <br /> D. ROCK LAYER DIlv�TSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area o�rocic <br /> layer:A x 0.83 = , <br /> �So • gpdx 0.83 sq.ft./gpd = c�a� sq. ft:►��o���" <br /> 2 Select width of rock layer(10 feet or less) = i o ft. <br /> 3. Length of rock layer=azea+width= R�g� <br /> s ft.+ ft. ft. ,.�.,.,.,.,.,.ti...�..�.,., <br /> L4S 4 q� � �� hf•IN•r J.t.1•��f�S�r•�'ir S t• <br /> �.�•�•ti•�•�•ti•ti•�.ti.ti•ti.ti•�•�.ti•ti <br /> M�����I�r�I�t�r•r/�IMMM�r�t� <br /> ,.,.�.ti..•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti idth 510 ft. <br /> r•r.r•r•r•ar•�•r r•r•r•rf•r•r• <br /> �•�•�•�•�•ti•ti•ti•ti•ti•�•ti.ti•ti.�.�.ti <br /> •r•r•r•r•r.r•�•r•r•r•�•�•r•r•r•r• . <br /> E. ROCK VOLUME ~- �'�' -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; �� <br /> �L�sN sq.ft. x .l oS ft. _�cu. ft. <br /> 2. Divide cu.ft.by 27 cu.ft:/cu. yd. to get cubic yards; <br /> ,�cu.ft. y 27=�2 cu. yd. <br /> 3. Multiply.cubic yazds by 1.4 to get weight of rock in tons; <br /> ,�cu.yd.x 1.4 ton/cu.yd. _�_tons. <br /> F. A�J�R�IDN�D� G l.l}v( l.0 Av✓1 Ab 'on NSdth 5iun Lbk <br /> 1. Percolation rate in top 12 inches of soil is ►2,� mpi ��a,��,w,� �-r ��• <br /> ��m�;,,�, Soil'Texture �,q°„��', �,°td <br /> Iw •b.wyas� <br /> Mdf� <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oa�sana 1�o l.00 <br /> d/ft� 0.1 to5 Sand 1.20 1.00 <br /> ,y� � 01 to 5 Fne Sand" 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1 S2 <br /> 3. Calculate adso rion width ratio b dividin rock la er �6 co 30 1.0�, o.� 2.� <br /> rP � Y 8 Y si co as s�ic�m o.s� 2•�w <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; ��� � 1.0�► o.as 2.6� <br /> 1.20 gpd/ft�y ,K s �d/�_ �.L'1 Slowerthan 120 CIaY 0.24 5.00 <br /> "Shc}+�vie+6 50lG or more d fine or vey fiae�and <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a•�-� x�_ft= a�•� ft <br />
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