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� ' � ' PRESSURE DISTRIBUTION SYSTEM Geotextile fabric .
<br /> "c:..•o.rs�ti•c•r gr �,y,•..r�l'�8�`P'���C:°Pt5"ra;aeg,�; 'at�,o:
<br /> .� .���a�.:9n'� fl..a.. R �.�n..4.ot. . :,.V',`�e�. v6o.nc:
<br /> p;.�r� c�'�a� d W� ;��•,.
<br /> 1. Select number of erforated laterals 5 � �A;°^� r'' .
<br /> P arter�nch rsHona aced O 3' --. . ,i.„.�x,.�
<br /> _ ,�. �: •�o,��.o qwaow
<br /> '•.^%.� i+.'e :;le'`.'�X'a4�' N'�j��.p.'s.'eP0 �C'i1GG• C;P+�.y''. �ooT[ry:y..
<br /> ' .v�A r' 'd;r b.o �p$•''s.�b! i' a. ' ' ' T:<• a ,J.Sjlt 0•.
<br /> 2. Select perforation spacing= ���` fee� �u'����°'=�'°"`"��a�����'��Y����"p�u`�°,-�`°�`�
<br /> �, o g';Lr.ti:es�ti�:pbb�:p.b� �p �.7AXw ac+'L.nar;u.•aeC?.'P�j.?
<br /> �c,,� _f?:C�:'�e�pG:d' L]'?�.Ca a �tr�y'{j..yra�y,J�.:a7T.:i� `.)'c<�:�
<br /> ' Perf Sizing 7/32"-1/4„
<br /> 3. Since perforations should not be placed closer than 1 ft. to Perf Spacing 1.5�-s�
<br /> the edge of the rock layer(see diagram),subtract 2 ft.from
<br /> the rock layer length. Perforation Discharges in gpm
<br /> �-2 ft. = 3��= feet. , head� � perforatian diameter
<br /> nches
<br /> ' (feet) 1/8" 3/16 7/32 1/4
<br /> 4. Determine the number of spaces between perforations. �,pa 0.t 8 0.42 0.56 o.7.a
<br /> Divide the length above by perforation spacing and round 2� 0.26 0.59 0.80 1.04
<br /> down to nearest whole number.
<br /> . . 5.0 0.41 0.94 1.26 1.65
<br /> Length perf. spacing= �`� ft.+ �=?�•��ft. _ !-� spaces a u�e�.o ro�r r«su,c��-r�mnv n«„as.
<br /> b u�e 2.o reet ror onym�em�.
<br /> . . . �3) �2) • Potanna�t«p��o9�+g
<br /> 5. Number of perforations i.s equal to one plus.the number of
<br /> perforation spaces . _ �+
<br /> Maximum number of quarter inch perforaflons pe
<br /> �spaces+ 1 = �p perforations/latexal lateral to guarnantee<10%discharge varlation
<br /> � Perforation
<br /> 6. Multiply perforations per lateral by number of laterals to � S�f�jg 1� 1� 2
<br /> get total number of.perforations. . 2,5 14 18 28
<br /> �����:� � 3.0 13 17 26
<br /> �� x �� _ .�c� perforat�ons.
<br /> 3.3 12 16 25
<br /> Calculate the squaze footage per perforation(6-10 sqft/perfl 4.0 11 15 23
<br /> system area: �, x �+� _ �vo�� ' 5.0 10 14 22
<br /> /��4� + �- 1 a..� sqft/perf
<br /> �a
<br /> w�o�o wurm �r n+o oF raeswne o�srmevnon srsren�
<br /> 7. Determine required flow rate by multiplying� . :
<br /> number of perforations by flow per perforation �
<br /> ����•�,•,y��e.,1:! �
<br /> ��
<br /> .� x��P� _�.8Pm �.��
<br /> r� � n rrt
<br /> 8. If laterals are connected to header pipe as shown on upper ��`""M
<br /> example,to select minimum required lateral diazneter;enter
<br /> table with perforation spacing and number of perforations �„►��,.W.�uTE�.�
<br /> .�.�an�»�T�,�,��
<br /> per lateral. Select minimum diameter for ,,,�,,,,,u„K,�
<br /> perforated lateral= • inches. � ' �. p,,,,,,,��"
<br /> �� „
<br /> �
<br /> 9. If perforated lateral system is attached to manifold pipe near. .�..�.,�»��«
<br /> the center,lower diagram,perforated lateral lextgth and - •-�����,,,��,
<br /> number of perforations per lateral will be appro�cimately one �,�, �, �
<br /> half of that in step 8. Using these values,select minimum �,,,��"'"`� �
<br /> diameter for perforated lateral= inches. �
<br />
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