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� � F-17 <br /> '':=:�' PiJMP SELECT'ION PROCEDURE <br /> -F!D PERiGRAT10N OF A PERFORATED LATERAL <br /> A Determine pump capacity: �...c.... <br /> Gravity Distribution ,.,,,.,, <br /> 1. Minimum suggested is 600 gallons per hour(10 gpm)to stay ahead of _ _:- � . �a� ���,w�,c<<,�,_ <br /> '!�w►s.�.�M.. �-'Yr�'N,.�1 ti...r�a.... <br /> water use rate. - .«.,..,.,.,�, <br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 _ ��;�+,�;�� <br /> gallons per hour(45 gpm)to prevent build-up of pressure in drop box. .,;�„��p ' .,� ,�.f.,. <br /> :: ::.. .... . �.���«. <br /> Pressure Distibution . '�:��,..,s,,.,..� °."°^.«�'...' <br /> 3.a. Select number of perforated laterals 3 , <br /> b. Select perforation spacing=�_feet �,�„'��„�'"° <br /> c. Sub/traf�2 ft.fcom the rock layer length. <br /> ��-2 ft._ _�� feet <br /> d. Deternune the number of spaces between perforadons. <br /> Length perf.spacing=�f t.+�ft._�spaces ,red pe�o�aon e <br /> e. 17 spaces+1=�s,�perforations/lateral " �g��P���c� <br /> f. Multiply perforations per lateral by number of laterals to I `� D�t,�e , � , <br /> 1 u o,A. �2 � <br /> g' �t total number of perforations. �,�� x��_�perforations. �� � �''°'` <br /> "��_�8Pm- . - . <br /> - � 1.Oa 0.56 0.74 <br /> SELECT'ED PUMP CAPACTI'Y�_gpm 2.�b �.80 1.�4 ' <br /> B.Determine head requirements: ' a.Use for single family homes <br /> l. Elevation difference between ump and point of discharge. b.Use for all other applications <br /> feet <br />��� 2. If pumping to a pressure distribudon system,five feet for pressure <br />� "'' required at manifold if gravity system,zero. <br /> _�feet <br /> ' 3. Friction loss <br /> ' a. Enter friction loss table with gpm and pipe diameter. � RP��8� <br /> Read friction loss in feet per 100 feet from table. Poinc of Ducharge <br /> F.L= '�,lo'-� ft/100 ft of pipe <br /> b. Determine total pipe length from pump to dischazge E1c�ation Diffaence <br /> poin� Add 25 percent to pipe length for fitting p�P g�S <br /> loss,or use a fitting loss chart. Equivalent pipe <br /> length-1.25 times pipe length= / F-18b <br /> �C� x 1.25= )�\feet 1S inch 2.0 inch 3.0 inch <br /> c. Calculate total friction loss by multiplying � F,;a;a„m��ooR�r�;a <br /> friction loss in ft/100 ft by equivalent pipe length. <br /> � Total friction loss= ��l�LJ x 1�-�� +100= ' .� feet 10 0.69 0.20 <br /> 12 0.96 0.28 <br /> 4. Total head required is the sum of elevation difference, 14 1.28 0.38 <br /> speciai head requirements,and total friction loss. 16 1.63 0.48 <br /> 18 2.03 0.60 <br /> � 20 2.47 0.73 0.11 <br /> � � + +�_ ?S 3.73 1.11 0.16 <br /> (1) (2) (3c) 30 5.23 1.55 0.23 <br /> � 35 7.90 2.06 0.30 <br /> 40 11.07 2.64 0.39 <br /> TOT'AL HEAD �,�feet � 45 14.73 3.28 0.48 <br /> 50 3.99 0.58 <br /> C Pump selection 6o s.6o o.s2 <br />'` 1. A pump must be selected to deliver at least <br /> �.-` <br />:;��= <br /> �_gpm (Step A) with at least ��feet of total head(Step B). <br />