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835 Hunt Farm Road - 30-118-23-43-0003
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Last modified
8/22/2023 4:28:08 PM
Creation date
2/28/2017 2:07:18 PM
Metadata
Fields
Template:
x Address Old
House Number
835
Street Name
Hunt Farm
Street Type
Road
Address
835 Hunt Farm Road
Document Type
Septic
PIN
3011823430003
Supplemental fields
ProcessedPID
Updated
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' � MOUND DESIGN WORKSHEET <br /> (For F1ows up to 1200 gpd) <br /> � , <br /> A. FLOW Esc;,,nuea s�.�,ge F1oa in ca11o�:pa n,y(g� ..� <br /> Fstimated y�_gpd <br /> N�anber <br /> or measured x 1.5 = gpd. �°�1l1f �`I �II 'I�'P�III �rv <br /> 2 30o us �so � <br /> 3 450 300 218 •t <br /> B. SFPTTC TANK LIQUID VOLUMES � a 6ao 3�s zs6 ..� <br /> 5 750 450 294 �. <br /> 6 900 525 332 � ' <br /> �—���C� g OILS 7 1 n50 600 370 �� <br /> �.,S�c-a�-1 v <br /> 8 1200 675 40B <br /> C. SOIIS(refer to site evaluadon) �� N,�� .� �� <br /> 1. Depth to restricting layer= 1 a. '`� y y'' inches B °� �, �,, <br /> 2 Depth of percolation tests = 1 a inches `°'�'"° `A'�"' <br /> 3. Perrnlation rate y,a mpi Zs«i�` i',oso°o i'.'s o <br /> 4. Land slope � % ;a 8 � � <br /> wQ 9 See C�g.C-6 (z 1� <br /> D. ROCK LAYER DIlV�NSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rocic <br /> layer:A x 0.83 = , <br /> t�o v . gpd x 0.83 sq.ft./gpd = ���'I sl sq. ft.�-lo`�0=5�'�`� <br /> 2 Select width of rock layer(10 feet or less) _ /0 ft. <br /> 3. L.ength of rock layer= area=width= R�� <br /> t � sq. ft.i �ft. = SS' ft. ti•ti•tiM•�•'ti.ti•MMti�M�•�K.�.ti.ti <br /> t�•1MN•I•r•�•1 l•r•r•�•t•�•1• <br /> �•�•1KH.�•ti•M��•�t•�•�•tiK•ti <br /> f•1•�N•1•�•r•f•/rN•t•r•f•I•f• �dth <_10 ft <br /> ~�T�:t�'••ti•MMMti•Mti•T•ti•ti•ti•ti <br /> • r l 1•1•1•fN•r f•I•Nr•I•�•J• <br /> - . 1•ti•tiwM•�•MS•wti•tiK•�K•1.t•ti <br /> .r.r.f.f.r.�.�.f.f.f•f.r.f.f.r.�. _. <br /> E. ROCK VOLUME ~— �'�` —� � � <br /> . ; <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; `- <br /> Sy� sq. ft. x I-c�a'ft. _�cu.ft. <br /> 2 Divide cu.ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> �u cu. ft. i 27= �.1 cu. yd. � <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> a 1 cu.yd. x 1.4 ton/cu. yd. _�tons. <br /> F. ADSORPTTON WIDTH G�''�K � �'✓1 ,+b va,►Kaa,s�, �bk <br /> 1. Percolation rate in top 12 inches of soil is mpi r�a,,,�,R,� �-- R.�.• <br /> M;,,,,k,�II,�, SoilTextur+e �.� �� <br /> tw <br /> .+�ad� <br /> 2 Select allowable soil loading rate from table; Faster c�an o.i oa�sana i 2o i.00 <br /> . y S gpd/ffi� 0.1 to5 Sand � 1.20 1.00 <br /> 0.1 to 5 Fne Sand 0•� 2•� <br /> 6 to 15 ndy Loam 0.79 1 S2 <br /> 3. Calculate adso hon width ratio b dividin rock la er 16 ro so [.oam o�� Z•� <br /> rP � Y S Y 31 to 45 s�ic r.�m o� 2•� <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; ��� �a �.o� o.a5 2.6� <br /> 1.20 gpd/ft2i,�y,,�gpd/ft�_ ��lo'� Slowerthan 120 Cjay 024 �_00 <br /> "Soil lvving 509G oe mare oE fu,e ar vey fi:+e suid. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> ��.�� x 1� ft=a�, ft � <br />
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