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F-17
<br /> P_U�SELECITON PROCEDURE
<br /> E!D PERFORA710N OF p p£qFpp4TEp LATERAL
<br /> A. Determine pump capacity: �,��,,,
<br /> Gravity Distribudon
<br /> .».M�
<br /> 1. Minimum suggested is 600 gallons per hour(10 gpm)to stay ahead of .��-;:...� �
<br /> water use rabe. - . �,,,,,,,�,�„*,� .►�w c..��w rm.K ca,�..
<br /> ' �n.N n„.��.a.r......
<br /> ���1���rwti 0�1
<br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 , . ►»�«.��,d���«�.o.,�a�.,�,
<br /> wN G�y Ir.r t�r
<br /> gallons per hour(45 gpm)to prevent build-up of pressure in drop box. .,;,,,,, � .�_�p«�,�.,.E,,.
<br /> Pressure Distibution . �,..,,.,,�,,,, �""`°"�«•�
<br /> Mnww M Ur�n�
<br /> 3.a. Select number oE perforated taterals
<br /> b. Select perforadon spacing= feeL ,�,;�,��,;+���•
<br /> c. Subtrad 2 ft from the rock layer length.
<br /> -2 ft._ " feet
<br /> d. Det� ernvne the nnmber of spaces between perforations.
<br /> Length perf.spacing= Et.+ ft.= spaces ' �,�p��n� e
<br /> e. spaces+1 = perforations/lateral �,gau«u p�a,;�,�ce tgp.,�
<br /> E. Multiply perforations per lateral by number oE laterals to �rg� �
<br /> get totat number of perforadons. �,� x � ��= perforations. �j ,�2�a� � "°'°""
<br /> g � X�� gP� 1.Oa 0.56 0.74
<br /> SELECI'E�PUMP CAPACTTY gpm 2.�b �.8� 1.0�
<br /> B.Determine head requirements: a.Use for single family homes
<br /> 1. Elevation difference between pump and point of discharge. b.Use for all other applications
<br /> a 9 feet
<br /> 2. If pumping to a pressure distribution rystem,five feet for pressure
<br /> required at manifold if gravity system,zero.
<br /> � feet
<br /> 3. Friction loss
<br /> a. Enter friction loss table with gpm and pipe diameter. ` Pipe La�gih
<br /> Read friction loss in feet per 100 feet from table. ' '
<br /> Point o!Dischar c
<br /> F.L._ �• �- f�/l00 ft of pipe �� g
<br /> �
<br /> b. Determine total pipe length from pump to discharge Elevation Dif[ercncc
<br /> poinG Add 25 percent to pipe length for fitting �p �.3
<br /> loss,or use a fitting loss chart. Equivalent pipe
<br /> length-1.25 times pipe length=
<br /> F-18b
<br /> 1 1� x 1.25= l.'� feet 1.5 inch 2.0 inch 3.0 inch
<br /> c. Calculate total friction loss by multiplying � fr;�a,����n�P.�
<br /> friction loss in k/100 h by equivalent pipe length. to 0.69 0.20
<br /> Total friction loss= ,�,�,x a l�'� +100=�_feet t2 0.96 0.28
<br /> 4. Total head required is the sum of eievation difference, 14 1.28 0.38
<br /> special head requimments,and total friction loss. 16 1.63 o.a8
<br /> 18 2.03 0.60
<br /> 20 2.47 0.73 0.11
<br /> a�+�+�_ 25 3.73 1.11 0.16
<br /> (1) (2) (3c) 30 5.23 1.55 0.23
<br /> 35 7.90 �2.Q� 0.30
<br /> 4Q _ ..l 1.07___ __�Z<64 039
<br /> TOTAL HEAD �feet a5 1a.73 3.28 O.aB
<br /> 50 3.99 0.58
<br /> 55 4.76 U.70
<br /> G Pump selection 6o s.6o o.s2
<br /> 1. A pump must be selected to deliver at least
<br /> ��gpm (Step A) with at least ��-t) feet of total head (Step B).
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