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' � ��::�;;:# 5 t�t���" ^'� ��. '�� 4 �a �'d � "� - <br /> �t�� - �� <br /> �;���.�'� � �" �� PUMP SELECTION PROCEDtJRE , <br /> � - � � a ��v r'h�� � ' - <br /> ;: :. .. . <br /> f :. ��u - � � ` <br /> �,. �l?�ter�nine pump capacity: . . <br /> � `��,��Gzay.ity dist�ribution �`: <br /> �-� - 1, Mininnum required discharge is 10 gpm 1 . <br /> ��" '""��"`' 2. Maximum sugg�ested dischar e is 45 m. For other <br /> r� g SP <br /> � . <br /> � ... . , ; establishments at least 10%greater than the water <br /> , - . <br /> � :': supply rate, but no faster t�tan the rate�t which effluent will flow . <br /> ���;:: ::-:aut:oE.the ; distribution device, � � <br /> k.: � $.=��'ressure distribution � , <br /> �.:'. . �. ,}�See pt'e�suYe dist�r�bution�work sheet � . . . � <br /> #_. _;.:.:,. _ _ <br /> :r < � >:� : ,.." <br /> •t::�:::�-=�rQm A or B Selected pump capacity: � gpm <br /> ���, y '' `� . . , � so9 treatmant system <br /> :���;��2.:Uetexm�ne pump head requixements. � �' & f norgs <br /> �` � A.ElevatiQn differ�nce between pump and point of discharge? a�.Q�+�" a'�`' .a` <br /> " ' =�_.,7 feet�_ - t� • <br /> ��;:;;::�::::��::�,; B.Special head requirement?(See Figure nt right-Sp�ciai H'ead qq,�,rohon <br /> � �Req�u�rements� � ...._. �erence �� . , <br /> ` �eet • <br /> , <br /> � :. .: C.Calcul�te Fric[ion loss .__. ....................... ....... .� . <br /> ;� �: I.�Select pipe diameter 2,a in � . . <br /> �_:�_ .�. � - 2. EnterFigure E 9 with gpm(lA or B) and pipe dia�teter Spectat Head Requ�rements : <br /> ; (C1)= �. '- Gravity,Distribudon U ft- - ` <br /> �. �Read friction Iogs in feet per�00 fee�from Figure E-9 p��ure Olstribuiion 5 ft <br /> :; . . <br /> ' ,,�.��ction Los�.��'�ft/100ft o€pipe <br /> � :-�� .- . . <br /> ,..:,..�;���?etermine t3tat pipe length fram pump discharge ta soil treat- <br /> 5����t_�scharge.point:Esi�mate by adding 25 gercent to p�pe length F.9:Fdcflon Loss in Plasfic Pipe <br /> ,t;� fo�ttiz1g loss..Total pipe length times 1.25=equzvalent pipe leng#h �er i W teef <br /> � �`� �'-��'7 feet x 1.25=�feet ' nom�nat <br /> lculate total friction lass b multi 1 in kicHon loss(C2) �PQ z ���� <br /> t °� � Y P Y b Row rate t.�" " ° <br /> ° v <br /> � ' '� � in ft/lOD fE by the equivaient pipe length(C3)and divide by 140. � <br /> ;��' `'',- ��.,,.;f t/IOOf#x .i��,_ +100= �' a.f t 20 2.47 0.�3 0.�t <br /> ��' '� ` � D Total�ead�required is the sum of elevation difference(A), 2�i� 9����:�1:t:i�:�.b:16� <br /> ,« . . . <br /> ' '� � al . �tead re ui�ements�B},and otal friction loss(C4) 5.23 `�o.2s � <br /> �* �' `�..-.. ft+ � E+ ?,J 35 4.96 0.30 . <br /> ,!r3:r''}. _ . . � �1 ✓ Y QO?:i;i:1&z 8.21:::�2.64:�i�:'A�39' . <br /> o� <br /> -= r 45 11 A7 328 0.48 <br /> � �,... :.� . : ��e� <br /> � � a �Total head: % _ 5a i3.a6 s.�v ass <br /> �z�, �°:•:��,. . �:��'���'���+°�o�� <br /> ,� �4� . . , <br /> �Y" �..� . 60 5.60 0.82 <br /> ��.� � � ��'ump.:se�ectiqn <br /> ���' �"� um must be selected o eliver at least ��'° �m � : e.4s 0.95 <br /> ` ��p p eet of total head(2D) 7 �'� �'� <br /> �''s� ;����or B)with at least � . <br /> .�� • ... �. <br /> �" "°�..,- . <br /> , �. . ,. ., <br /> r; �..:._ • _ <br /> �z.,� . . M <br /> r ���reby certify.tb�t I have completed thls work in accor�lar►ce with applicable ordinances, rules and laws. <br /> '�%� c : � . . . <br /> � � ' •e p (UCense� (date) <br /> f�.,ib4' �S��I{"fUC`� �^ <br /> �1.`::jt�4:� . <br /> wi: t <br /> ;:fiy::;��:t • • ' <br /> Y'-:r.:;� 1 . _ . . <br />