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2011-00901 - new septic
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265 Hollander Road - 25-118-23-43-0016
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2011-00901 - new septic
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Last modified
8/22/2023 4:15:54 PM
Creation date
2/22/2017 1:01:36 PM
Metadata
Fields
Template:
x Address Old
House Number
265
Street Name
Hollander
Street Type
Road
Address
265 Hollander Road
Document Type
Septic
PIN
2511823430016
Supplemental fields
ProcessedPID
Updated
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� 1VIOUND DESIGN WORK SHEET � <br /> (For Flo�vs up to 1200 gpd) <br /> A. �'lverage Design FLOW � A-t: Estimated Sewage Flows in Gallons per Day <br /> ��'�'` � nu--__- <br /> Estimated to0 C� gpd (see figure A-1) i bedrooms c�ass� C�ass n qass��� c�ss�v <br /> or measured x 1.5 (safety factor) __=�gpd 2 � 225 ��o � <br /> 3 - 450 300 218 ofthe <br /> I 4 b00 375 256 values <br /> B. SEPTIC TANK Capacity � 5 �so �5p 2q4 in tne <br /> � 6 900 525 332 Class I, <br /> j 7 1050 600 370 II,or III <br /> a-t►ac� � gallons (see figure C-1) i <br /> �x�s-tiN.� 'S�R�.ti�t-s w�Ns, �,� wt�-5� -c�.��,�-5� 8 1200 675 408 columns. <br /> C. SOILS (refer to site evaluation) � c-i: • T�tce • �� i <br /> Number of Miniawm Liqnid liqaid capacity vrit6 ��d�� <br /> 1. Depth to restricting layer= a.ca�,.�,43.1 fei t B� ���r s�a� i;n� <br /> 2. Depth of percolation tests = !. � fe�et za� �so �i�s �� <br /> 3. Texture GL��(Lv� 4 SA��t u��, � 3 o�a �000 �soo � <br /> Percolation rate �t. � mpx � �Ss�9 � 3o�ou 30°° <br /> 4. Soil loading rate • �.c� �nd/sqft(see f�'igure D-33) <br /> 5. Percent land slope --� % i <br /> I <br /> D. ROCK LAYER DIMENSIONS i <br /> 1. Multiply average design flow (A)by 0.83 to obtain required rock layer area. <br /> c�u o gpd x 0.83 sqft/gpd =� ft <br /> 2. Determine rock layer width � 0.83 sqft/gpd x inear Loading Rate (LLR <br /> 0.83 sqft/gpd x I �, gpd/sqft= J�_ft Mound LLR <br /> 3. Length of rock layer= area=width = ' <br /> 4`l�r(-=sqft(D1)� I� ft (D2) = SU ft 4 < 120 M PI <� 2 <br /> E. ROCK VOLUME � > 120 M PI < C� <br /> 1. Multiply rock area (Dl)by rock depth of 1 ft t get cubic feet of rock <br /> 4 � � sqft x 1 ft= 4��d cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yardsl <br /> � � � cuft �-27 cuyd/cuft= 1 � cuY <br /> 3. Multiply cubic yards by 1.4 to get weight of ro in tons <br /> _].�cuyd x 1.4 ton/cuyd = a�U tons <br /> -----_ __ _ <br /> � D-33: Absorption Width Sizing Table <br /> F. SEWAGE ABSORPTION WIDTH �°'"�°^�"� ��� <br /> � in Minutu per Soil Texture Gallans AAsorption <br /> I Mpt w�Yf� Ra�io <br /> Fester than S Cwrse Sand 1.20 1.00 <br /> Medium Sand <br /> Absorption width equals absorption r�tio (See Figur D-33) `'""'YS"� <br /> times rock layer width (D2) � � -, o 0 0. <br /> o , . <br /> �:�� x I p ft= 2� 0, u ft +�►�� �,a•y o.;5 z.6� <br /> sui c�.y to.m <br /> 6I to 120 Silry Qay 0.24 5.00 <br /> Su�d pey <br /> Slower l20' <br /> •Srnem dni�ned(or Nae aits�sw be aiEer or pafomrecc <br /> Ii <br /> I <br /> 1 <br />
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