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Mound Design Worksheet (For flows up to 1200 gpd) <br /> All boxed�ectangles must be eMered,the rest wil!be calculated. Ar 1;&�a�d Sewope Howc in Galan Per DaY <br /> A. FLOW <br /> Estimated 750 gpd(see figwe A-1) "ur '�° <br /> or measured x 1.s(safery fac�or>= 0 9� be�oom� Cf�oa� aa�s u aaas�u aacs�v <br /> 2 300 225 180 60% <br /> B. SEPTIC TANK LIQUID VOLUME3 3 150 300 218 of 1he <br /> Septic tank capacity 2250 galions(see figu►+a G1) 4 600 315 256 val,es <br /> 5 750 450 294 h the <br /> C. SOILS(Site evaluation data) 6 900 525 332 Go�I, <br /> 1. Depth to restricting layer= 1.75 feet 1 IOSO 600 370 �,a NI <br /> 2. Depth of percolation tssts= 12 inches 8 1200 675 �08 cdurns. <br /> 3. Te�cture sil loam <br /> 4. Soit loading rate(see F'gure D-33 0.5 gpol ft <br /> Percolation rate 35 MPI <br /> 5. 96 Land Slope 6 % D-33: Abrorptbn Wl�h Slzlde Tabk <br /> Percolatioo R�tc l.o�din�Rate <br /> C-1: Se k Tapk cides(in alloas) '°M��.. s�r� c.►� ,w�«�oo <br /> Number of Minimum Liquid Liquid capadty with Vquid capecity P.�«�s M�� �.zo �.00 <br /> Bedrooms Capaary g�g��g� w�th disposal& ,,�.s,,,� <br /> lift iaside <br /> 2orless 750 1125 lSpp siw�s s�u o:so z�o <br /> 3 or� 1000 1500 200p aa w 6o ayp�� o.as 2 s� <br /> S a 6 1500 2250 � <br /> 7,S or 9 2000 3000 6�w i xo sv�y cx.y o.z, s.00 <br /> �nna c�y <br /> o.rer w�c� • <br /> . . �ayww arare far Wu�r aoi4 nw M orr w prfoara�q <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design i�w(A)by 0.83 to obtain required area of rodc layer:Item A x 0.83= <br /> 750 gpd x 0.83 fl�gpd= 622.5 ft� <br /> 2. Determine rodc layer width =0.83 ft�/gpd x Linear Loadin Rate(LLR)(see LLR chart) <br /> 0.83 ft/gpd X 12 = 10.0 ft <br /> LLR Chart <br /> Pe�ic Rate LLR <br /> <120 MPI <=12 <br /> >=120 MPI <=6 <br /> 3. Length of rodc layer=area divided by width= <br /> 622.5 fl� / • 10 feet= 62.5 feet <br /> E. ROCK VOLUME <br /> 1, Multiply rock area by rodc depth to get cubic feet of rodc <br /> 622.5 X 1 ft= 622.5 ft3 <br /> 2. Divide fC�by 27 fC�lyd3 to get cubic y8rds <br /> 622.5 ft� / 27 = 23.1 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rodc in tons; <br /> 23.1 yd3 X 1.4 toNyd3 = 32.3 tons <br /> F. ABSORPTfON WIDTH <br /> 1. tion width uals absorption ratio(see Figure D-33j times rodc layer width <br /> 2.4 x 10.0 ft = 24.0 R <br />