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PRESSURE DISTRIBUTION SYSTEM - Trenches
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<br /> R 1�10� QY d�f
<br /> AU boxed►ectangbs must ba entsreal,dhe mst wAl be ca�Watsd. a-or.�k
<br /> PerE 9iziryj 7/16^-�ia..
<br /> Porf 9pwc ng 7.5'-S'
<br /> 1. Select number of perforated laterals: 03
<br /> 2. Select perforation spacing= 03 ft Er�,,,�,,,,,,,,�,o,,,,�,.,ti,„�.,a,,,�,,P.,b,�,,,
<br /> �a�.a a a�rar+i..aox a.�nQo.�e.w�r�
<br /> 3. Since perForations should not be placed closer that 1 foot to �
<br /> the edge of the rock layer(see diagram), subtract 2 feet from o
<br /> the rock la er len th z.s e ,4 ,e �e
<br /> 63 -2 ft= 61 ft s.o 8 13 n �a
<br /> rock layer length '.' ' 12 16 �
<br /> ao � n is n
<br /> 5.0 6 10 14 22
<br /> 4 Determine the number of spaces between perforations.
<br /> Divide the length (3)by perForation spacing (2)and round down to nearest whole number.
<br /> Perforation spacing= 61 ft/ 3 ft= 20 spaces
<br /> 5. Number of perforations is equal to one plus the number of perForation spaces(4).
<br /> 'Check figure E-4 to assure the number of pefi�rations per lateral guarantees
<br /> < 10%discharg�e variation.
<br /> 20 spaces+ 1 = 21 pertorations/lateral
<br /> 6. A..Total number of pertorations=pertorations per lateral(5)times number of laterals(1).
<br /> 21 perfs/lat x 3 laterals= 63 perforations
<br /> E-6: Perfcroiion�Iccharpe in flpm
<br /> B. Calculate the square footage per pertoration.
<br /> Should be 6-10 sqft/perf. Does not apply to at-grades. P�to�a��diameter
<br /> 1. Rock bed area= rock width (ft)x rodc length(ft) ��t� J16 7/32 1/4
<br /> 10 ft x 63 ft= 630 ft� 1.pa 0.18 0.42 0.56 0.74
<br /> 2. Square foot per perforation = Rock Bed Area/number of perts(6)
<br /> 630.0 ft/ 63 perfs = 10.0 ft2/perf 2•ob o.26 0.59 O.so t.oa
<br /> 5.0 0.41 0.94 1.26 1.65
<br /> 7. Determine required flow rate by multiplying the total number a Ute 1.0�mt tor arr,qe-rurcir�h��rnc,s.
<br /> of perforations(6A)by flow per rforations(see figure E�) n z. r ,r << � rn� ��.
<br /> 63 perfs x 0.56 gpm/perfs= 35.3 gpm
<br /> 8. If laterals are connected to header pipe as shown ��=�«•���°������ � �
<br /> in Figure E-1, to sel�ct minimum required lateral J � cµ m��4
<br /> oro�Y �`' �'�l~ � ��"'�L/�
<br /> diameter, enter figure E-4 with perforation spacing(2)and �-=--'�' -=��^.
<br /> number of perForations per lateral(5). ,�= ��! ,'��
<br /> ��-- ,vy,�a,��.,����,
<br /> ui r.�cn i�:,m,o•s.�c _�
<br /> Rpur�E-1:ManMold looaNtl d End ef i1nNm
<br /> Select minimum diameter for perforated laterals= Qinches
<br /> 9. If pe�forated lateral system is attached to manifold pipe �FxM�� -=���°�
<br /> near the center, like Figure E-2, perforated lateral length (3) � ����� � _�'
<br /> .�--=�- � -
<br /> �-�-�"�\"�„=.`==' __.
<br /> and number of perforations per lateral(5)will be approximately fy�- ��----
<br /> one half of that in ste 8. Usin these values, select �'-� =���
<br /> P 9 � ``�--�;�.v:�:,:.�,.r
<br /> �'.- _- �=",�m�,,.�
<br /> minimum diameter for perforated lateral= 02 inches. __- �
<br /> �.;,,.. �.,.�
<br /> I he� cert' t I hav pleted this work in accordance with all applicable or 'nan s, rules and laws.
<br /> (signature) �J U� (license#) (date)
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