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T� °1�-� Job#�� <br /> P.eseww.. - <br /> Univetsi p#Minneso�a IYlound Des�gn Worksheet <br /> c�m��x s� <br /> a � <br /> � soo �a�s�e r��-+) <br /> ar maeetrred � x 1�(�f►�_ � 9P� <br /> B. SEPTIC TMN(LJQUD V'OLU�S <br /> ���y ZOOp gallons(see Ifg�xe F1) <br /> rNmberd�ar�kaJoomPartrne�ts 0 <br /> E11'Auuent F�er(yeslno) �es <br /> G1 Tank C�padly in G�Mo� <br /> Nixr�ber d �m Capadty with Capedly wNh <br /> Bediooms Garb.Disp. Disp.end L1ft <br /> ar � <br /> 3 a 4 1500 <br /> 5or6 � <br /> 7,8or9 3000 <br /> C. SOLS(S11e sve�N�a(ion deta) <br /> 1. Deptli 1��slrk�ng tayer 2.1 teet <br /> 2. Deph d petcolaaon le�s= 12 inc�es <br /> 3. Teocdx�e � <br /> 4. Sh co�ing ra0e(see Figrxe a33) 0.60 9Pd�� <br /> pe�ooiatlon ra�e 6 MPI <br /> 5. q�(�� 14.0 % <br /> D. ROCK LAYER DY�101� <br /> 1. M�iply ave�ge design flow(A)bY 0.83�o obtain required area of rodc layer:Mem A x 0.83= <br /> 600 gpd x 0.83 it�lgpd= 500 it� <br /> 2. Deiertrrne rock layer widlh =0.8311`Igpd x Linear Loading RaEe(LLR)(see LLR d�t <br /> 0.$3 il�l�d x 12.00 = 10.0 ft <br /> LLR Cl�t <br /> Pe�C Ra�e LLR <br /> <120 MPI <=12 <br /> x120 MPI � <br /> 3. Lenglh d rodc layer=ar�divided by wid�_ <br /> 500.0 it� / 10.0 feet= 50.0 ft <br /> E. ROCK VOLUME <br /> 1. Mulfiply rodc ar�a by rodc deqh b get cubic Teet af rodc <br /> 500.0 X 1 A ft= 500.0 ft3 <br /> 2. Divide 1t�by 27 fC�/yd3 to get cubic yards <br /> 500.0 iC� ! 27 = 18.5 yd3 <br /> 3. Mu�ipyl cubic yards by 1.4 to gel weigM d r�ndc in lons; <br /> 18.5 yd3 X 1.4 taNyd� = 25.9 tons <br /> Page 1 of 5 <br />