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2008-00124 - septic
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205 Hollander Road - 25-118-23-44-0011
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2008-00124 - septic
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Last modified
8/22/2023 4:16:16 PM
Creation date
2/22/2017 9:00:57 AM
Metadata
Fields
Template:
x Address Old
House Number
205
Street Name
Hollander
Street Type
Road
Address
205 Hollander Road
Document Type
Septic
PIN
2511823440011
Supplemental fields
ProcessedPID
Updated
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, 1�✓TOUND DESIGN WORK SHEET (For Flows u to 1200 d) <br />`', A. 'Average Design FLOW A-l: Estimated Sewage Fiows In Gollons per Day <br /> � num er o <br /> Estimated �� gpd (see figure A-1) bedrooms ciass i ciass u ciau ui ciass iv <br /> or measured x 1.5 (safety factor) = gp 2 300 225 �8o bo% <br /> 3 450 300 218 of the <br /> 4 600 375 256 values <br /> B. SEPTIC TANK Capacity 5 750 450 294 in the <br /> 6 900 525 332 Class I, <br /> 7 1050 600 370 II, or III <br /> Z' r�'T� galloriS (see figure G1) �� � �' 8 1200 675 408 columns. <br /> 1 - (f�c �'a.�-�-E.�l �1..�' �1lc 't'��.!l�C. <br /> C. SOILS (refer to site evaluation) C-1: Se ticTankCa acities(in alioas <br /> Liquid capacity <br /> ;Vumber of Minimum Liquid Liquid capaciry with W��disposal& <br /> 1. Depth to restricting layer= � feet Bedrooms Capacity garbagedisposal lihiaside <br /> 2. Depth of percolation tests = i feet z o���s �so iiu 15� <br /> 3. Texture �E �h�-o�° 3o�a i000 isoo Z� <br /> t'� • 5 or 6 1500 2250 3� <br /> Percolation rate i��.$ mpi (�-t'�) �,s°�9 Z000 3000 <br /> 4. Soil loading rate . �uG Qvd/sqft (see figure D-33) <br /> � <br /> 5. Percent land slope ^ % � �„� ��„�.r3�� r� <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow (A) by 0.83 to obtain required rock layer area. <br /> (c�vC gpd x 0.83 sqft/gpd = � sqft�x i.oj <br /> 2. Determine rock layer width = 0.83 sqft/gpd x linear Loading Rate LLR <br /> 0.83 sqft/gpd x �Z- �ud/sqft = �� ft Mound LLR <br /> 3. Length of rock layer = area= width = <br /> �� sqft (Dl) = t o ft (D2) = Gs� ft < 120 M PI <� 2 <br /> E. ROCK VOLUME > 120 MPI < C� <br /> 1. Multiply rock area (D1) by rock depth of 1 ft to get cubic feet of rock <br /> �� sqft x 1 ft = ��cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> �"'� cuft = 27 cuyd/cuft = Z 3 cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons <br /> �-3 cuyd x 1.4 ton/cuyd = s3 tons <br /> D-33: Absorpdon Width Sizing Table <br /> F. SEWAGE ABSORPTION WIDTH PercolauonRate LoadingRate <br /> in Minut�s per Soil Tezcure Gallons Absorpuon <br /> Inch per day per Ratio <br /> MPI s uare foot <br /> Faster than 5 Coarse Sand I.20 1.00 <br /> Absorption width equals absorption ratio (See Figure D-33) �°Ys a° <br /> � <br /> times rock layer width (D2) <br /> 16 u>30 Loam 0.60 �.00 <br /> 31 to 45 Silt Loam 0.50 2.40 <br /> �� x �� f t= � ft 46 i�60 Sandy CI�Y Ln 0.45 �.6� <br /> Silty Clay Loam <br /> 61 m 120 Silry Clay 0.24 5.00 <br /> Sandy Clay <br /> Cla <br /> Sl�iwer Ih•rn 120• <br /> •Sysc<m�csigneJ fot U�ese soils muu be ahnr ur perfom�ance <br />
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